Answer:
all work is shown and pictured
The correct question is
<span>A student ate 3/20 of all candies and another 1.2 lb. Another student ate 3/5 of the candies and the remaining 0.3 lb. Altogether, what weight of candies did they eat?</span>
let
x-------> total <span>weight of candies
we know that
x=(3/20)*x+1.2+(3/5)*x+0.3
</span>x=(3/20)*x+(3/5)*x+1.5----> multiply by 20----> 20x=3x+12x+30
20x=15x+30
20x-15x=30
5x=30
x=6 lb
the answer is
6 lb
Answer:
4
Step-by-step explanation:
f(p) = 3p-2
Let p=2
f(2) = 3*2-2
= 6-2
= 4
Opposite sides of a parallelogram are equal lengths, so ...
... AB = CD
... 6x +30 = 2y -10
and
... BC = AD
... 2x -5 = y -35
_____
The equations can be put in standard form to get
... 3x -y = -20
... 2x -y = -30
Subtracting the second from the first, we get
... x = 10
Solving for y, we have
... y = 2x+30 = 2·10 +30 = 50
The values of x and y are x=10, y=50.
_____
AB = 6x+30 = 90
BC = 2x-5 = 15
Step-by-step explanation:
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