I’m slow , can i get help on this asap please ?

A certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder. In

lord [1]

Answer:

95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

Step-by-step explanation:

We are given that a certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder.

A random sample of 1000 males, 250 are found to be afflicted, whereas 275 of 1000 females tested appear to have the disorder.

Firstly, the pivotal quantity for 95% confidence interval for the difference between population proportion is given by;

P.Q. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of males having blood disorder= $\frac{250}{1000}$ = 0.25

$\hat p_2$ = sample proportion of females having blood disorder = $\frac{275}{1000}$ = 0.275

$n_1$ = sample of males = 1000

$n_2$ = sample of females = 1000

$p_1$ = population proportion of males having blood disorder

$p_2$ = population proportion of females having blood disorder

Here for constructing 95% confidence interval we have used Two-sample z proportion statistics.

So, 95% confidence interval for the difference between the population proportions, ( $p_1-p_2$ ) is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ < ${(\hat p_1-\hat p_2)-(p_1-p_2)}$ < $1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ) = 0.95

P( $(\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ < ( $p_1-p_2$ ) < $(\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ) = 0.95

95% confidence interval for ( $p_1-p_2$ ) =

[ $(\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ , $(\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ]

= [ $(0.25-0.275)-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} }$ , $(0.25-0.275)+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} }$ ]

= [-0.064 , 0.014]

Therefore, 95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

8 0

3 years ago

The semi-circle has a diameter of 8. What is the perimeter of the semi-circle?

skad [1K]

Answer:

roughly 12.56 units

Step-by-step explanation:

Since the perimeter of a circle is 2*pi*r, we can divide it by two or multiply by half in order to find the perimeter of a semicircle

half of the diameter is the radius, so 8/2 =4, r=4

Plug in what we know...

C=2*pi*4

Solve

2*3.14*4

25.12

divide by 2

25.12/2=12.56

12.56 units is the perimeter

6 0

3 years ago

Read 2 more answers

Simplify this expression. <img src="https://tex.z-dn.net/?f=%5Cfrac%7B4%5E%7B9%7D%20%7D%7B4%5E%7B3%7D%20%7D" id="TexFormula1

gogolik [260]

9x9x9x9divide by 4x4x4

3 0

3 years ago

Read 2 more answers

PLS HELP WILL GIVE BRANLIEST

AnnZ [28]

Answer:

she took 13 classes that were worth 3 credits

Step-by-step explanation:

well we know that some of the classes are worth 3 and some are worth 4 and that all of these together = 59 so your first equation would be

3x+4y=59

x would be the number of classes worth 3 credits and y would be the number of classes worth 4 credits.

then it says the total number of classes that they took was 18 so we know that

x + y =18.

you want to solve for the number of 3 credit classes so lets go ahead and get rid of the y values. SO you need you multiply the x+y equation by 4

4x+4y=72

then subtract 4x+4y=72 from 3x+4y=59 to get

-x = -13

and then x is a negative so you need to divide -1 from both sides and you get that she took 13 classes that were worth 3 credits.

3 0

2 years ago

A retailer incurs a fixed cost of N$ 500 when purchasing sugar for his stock. He pays N$ 10.00 per packet which he resells at N$

Arada [10]

Answer:

100 packets

Step-by-step explanation:

Given :

Cost = fixed cost + variable cost

Fixed cost = $500

Variable cost = $10

Sales price = $15

Let :

Number of packets = x

To break even :

fixed cost + variable cost = sales made

500 + 10x = 15x

500 = 15x - 10x

500 = 5x

x = 500 / 5

x = 100

100 packets

8 0

3 years ago