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siniylev [52]
3 years ago
10

I’m slow , can i get help on this asap please ?

Mathematics
1 answer:
makkiz [27]3 years ago
5 0
140°
Pentagons add up to 540° so if you add all the degrees you get 400° and if subtracted from 540° you get 140°
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A certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder. In
lord [1]

Answer:

95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

Step-by-step explanation:

We are given that a certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder.

A random sample of 1000 males, 250 are found to be afflicted, whereas 275 of 1000 females tested appear to have the disorder.

Firstly, the pivotal quantity for 95% confidence interval for the difference between population proportion is given by;

                        P.Q. = \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }  ~ N(0,1)

where, \hat p_1 = sample proportion of males having blood disorder= \frac{250}{1000} = 0.25

\hat p_2 = sample proportion of females having blood disorder = \frac{275}{1000} = 0.275

n_1 = sample of males = 1000

n_2 = sample of females = 1000

p_1 = population proportion of males having blood disorder

p_2 = population proportion of females having blood disorder

<em>Here for constructing 95% confidence interval we have used Two-sample z proportion statistics.</em>

<u>So, 95% confidence interval for the difference between the population proportions, </u><u>(</u>p_1-p_2<u>)</u><u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                             of significance are -1.96 & 1.96}  

P(-1.96 < \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < {(\hat p_1-\hat p_2)-(p_1-p_2)} < 1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } ) = 0.95

P( (\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < (p_1-p_2) < (\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } ) = 0.95

<u>95% confidence interval for</u> (p_1-p_2) =

[(\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }, (\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }]

= [ (0.25-0.275)-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} }, (0.25-0.275)+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} } ]

 = [-0.064 , 0.014]

Therefore, 95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

8 0
3 years ago
The semi-circle has a diameter of 8. What is the perimeter of the semi-circle?​
skad [1K]

Answer:

roughly 12.56 units

Step-by-step explanation:

Since the perimeter of a circle is 2*pi*r, we can divide it by two or multiply by half in order to find the perimeter of a semicircle

half of the diameter is the radius, so 8/2 =4, r=4

Plug in what we know...

C=2*pi*4

Solve

2*3.14*4

25.12

divide by 2

25.12/2=12.56

12.56 units is the perimeter

6 0
3 years ago
Read 2 more answers
Simplify this expression.<br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B4%5E%7B9%7D%20%7D%7B4%5E%7B3%7D%20%7D" id="TexFormula1
gogolik [260]

9x9x9x9divide by 4x4x4

3 0
3 years ago
Read 2 more answers
PLS HELP WILL GIVE BRANLIEST
AnnZ [28]

Answer:

she took 13 classes that were worth 3 credits

Step-by-step explanation:

well we know that some of the classes are worth 3 and some are worth 4 and that all of these together = 59 so your first equation would be

3x+4y=59

x  would be the number of classes worth 3 credits and y would be the number of classes worth 4 credits.

then it says the total number of classes that they took was 18 so we know that

x + y =18.

you want to solve for the number of 3 credit classes so lets go ahead and get rid of the y values. SO you need you multiply the x+y equation by 4

4x+4y=72

then subtract 4x+4y=72  from 3x+4y=59 to get

-x = -13

and then x is a negative so you need to divide -1 from both sides and you get that she took 13 classes that were worth 3 credits.

3 0
2 years ago
A retailer incurs a fixed cost of N$ 500 when purchasing sugar for his stock. He pays N$ 10.00 per packet which he resells at N$
Arada [10]

Answer:

100 packets

Step-by-step explanation:

Given :

Cost = fixed cost + variable cost

Fixed cost = $500

Variable cost = $10

Sales price = $15

Let :

Number of packets = x

To break even :

fixed cost + variable cost = sales made

500 + 10x = 15x

500 = 15x - 10x

500 = 5x

x = 500 / 5

x = 100

100 packets

8 0
3 years ago
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