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Wewaii [24]
3 years ago
13

A bag contains 5 red poker chips, 3 blue poker chips and 7 white poker chips. Two chips are drawn without replacement. Find the

probability that the first and second are red.
Mathematics
1 answer:
prohojiy [21]3 years ago
4 0
5 red, 3 blue, 7 white.....total of 15

probability of 1st drawn being red : 5/15 reduces to 1/3
without replacement
probability of 2nd being red : 4/14 reduces to 2/7

probability of both : 1/3 * 2/7 = 2/21 <==
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Really could use help here.
marishachu [46]

Answer:

\mathsf {y =\frac{15}{7}x } < \mathsf {y=\frac{13}{6}x } < \mathsf {y=\frac{11}{5}x } < \mathsf {y=\frac{21}{9}x } < \mathsf {y= \frac{19}{8}x}

Step-by-step explanation:

<u>Finding the unit rate of the graph</u> :

  • Take 2 points and find the slope
  • ⇒ (0,0) and (12, 25)
  • ⇒ m = 25 - 0 / 12 - 0
  • ⇒ m = <u>25/12</u>
  • The equation is : <u>y = 25/12x</u>

Now, the equations with greater unit rates (in increasing order) are :

  • \mathsf {y =\frac{15}{7}x } < \mathsf {y=\frac{13}{6}x } < \mathsf {y=\frac{11}{5}x } < \mathsf {y=\frac{21}{9}x } < \mathsf {y= \frac{19}{8}x}
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Here is the answer
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Conrad had $110 to spend on 9 cheese pizzas for a party. After buying them, he had $8.75 left. How much did each pizza cost? Sho
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Subtract 110 and 8.75 and you get 101.25 then divide that by 9 and you get 11.25

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