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Wewaii [24]
3 years ago
13

A bag contains 5 red poker chips, 3 blue poker chips and 7 white poker chips. Two chips are drawn without replacement. Find the

probability that the first and second are red.
Mathematics
1 answer:
prohojiy [21]3 years ago
4 0
5 red, 3 blue, 7 white.....total of 15

probability of 1st drawn being red : 5/15 reduces to 1/3
without replacement
probability of 2nd being red : 4/14 reduces to 2/7

probability of both : 1/3 * 2/7 = 2/21 <==
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For the equation y= x + 5, find the value of y when
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Answer:

a) 3 b) 5 c) 7 d) 9

Step-by-step explanation:

For this, you want to replace x in the equation y=x+5 with each of the values listed.

For the first one, -2, the equation becomes y=-2+5, which is solved to y=3.

For the second one, 0, the equation becomes y=0+5, which is solved to y=5.

For the third one, 2, the equation becomes y=2+5, which is solved to y=7.

For the last one, 4, the equation becomes y=4+5, which is solved to y=9.

**This content involves solving algebraic equations with a known variable, which you may wish to revise. I'm always happy to help!

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3 years ago
17.09 + 3.98 BENCHMARK!!!
Ahat [919]
21.07 beacuse when you add them all up you get that..
 
3 0
3 years ago
Read 2 more answers
Someone just answer this math question thingie lol. you’ll get 33 points G
Stels [109]

1) (-2x+4)+(x-6) is simplified into =-x-2

2)  (uv-3)+(4uv+1)  is simplified into 5uv-2\\

3) (11x-8)-(2x+3) is simplified into -9x-11

4) (x^2-4)-(x-2) is simplified into x^2-x-2

5) (12-3t-7t^2)+(1+3t-t^2) is simplified into -8t^2+13

Step-by-step explanation:

We need to solve the polynomials.

1) (-2x+4)+(x-6)

Solving:

(-2x+4)+(x-6)\\=-2x+4+x-6\\Combining\,\,like\,\,terms:\\=-2x+x+4-6\\=-x-2

So, (-2x+4)+(x-6) is simplified into =-x-2

2) (uv-3)+(4uv+1)

Solving:

(uv-3)+(4uv+1)

Expanding:

=uv-3+4uv+1\\Combining\,\,like\,\,terms:\\=uv+4uv-3+1\\=5uv-2\\

So,  (uv-3)+(4uv+1)  is simplified into 5uv-2\\

3) (11x-8)-(2x+3)

Solving:

(11x-8)-(2x+3)

Expanding:

=11x-8-2x-3\\Combining\,\,like\,\,terms:\,\,\\=11x-2x-8-3\\=-9x-11

So, (11x-8)-(2x+3) is simplified into -9x-11

4) (x^2-4)-(x-2)

Solving:

(x^2-4)-(x-2)

Expanding:

=x^2-4-x+2\\Combining\,\,like\,\,terms:\\=x^2-x-4+2\\=x^2-x-2

SO, (x^2-4)-(x-2) is simplified into x^2-x-2

5) (12-3t-7t^2)+(1+3t-t^2)

Solving:

(12-3t-7t^2)+(1+3t-t^2)

Expanding:

=12-3t-7t^2+1+3t-t^2\\Combining\,\,like\,\,terms:\\=12+1-3t+3t-7t^2-t^2\\=13+0t-8t^2\\=-8t^2+13

So, (12-3t-7t^2)+(1+3t-t^2) is simplified into -8t^2+13

Keywords: Solving Polynomials

Learn more about solving Polynomials at:

  • brainly.com/question/12700460
  • brainly.com/question/1414350
  • brainly.com/question/4142886

#learnwithBrainly

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3 years ago
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Write an equation and solve: Twice a number, increased by 3 is 7.
brilliants [131]
The equation is 2x+3=7
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2x=4
divide both sides by 2
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