A bag contains 5 red poker chips, 3 blue poker chips and 7 white poker chips. Two chips are drawn without replacement. Find the
probability that the first and second are red.
1 answer:
5 red, 3 blue, 7 white.....total of 15
probability of 1st drawn being red : 5/15 reduces to 1/3
without replacement
probability of 2nd being red : 4/14 reduces to 2/7
probability of both : 1/3 * 2/7 = 2/21 <==
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Answer:
2.25
Step-by-step explanation:
.
V = 2s^3
v = 2(3.5)^3 = 2(42.875) = 85.75 cubic units
4*sqrt of x - 1 = 63; x = 256
