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Answer :- ( B ) 81 π cubic feet
Explaination :-
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The vertex form of equation of a parabola:
(h, k) - vertex
We have the vertex (-0.5, 2.3). Therefore h = -0.5 and k = 2.3.
Substitute:
We have the point (5, 2.75). Put the coordinstes of the point to the equation of parabola:
Answer:
49%
Step-by-step explanation:
First, find 55% of 9 pounds.
55% = 0.55
9 × 0.55 = 4.95
Next, find 40% of 6 pounds.
40% = 0.4
6 × 0.4 = 2.4
Add the two values together.
4.95 + 2.4 = 7.35
Find the percentage 7.35 is of the total weight (15 pounds).
7.35/15 = 0.49
0.49 = 49%
49% of the new mixture is peanuts.
Get out your graphing paper. Since the slope formula is y=mx+b, we can say that +4 is b, which also stands for the y-intercept. Because +4 is the y intercept, place a point on (0,4). Then, using the slope (m or 3), we can figure out where the second point will go.
Slope is another word for rise over run. In this case it is 3/1 because that is what 3 is when converted to a fraction. So, from (0,4), we go up 3 and over to the right by 1 to plot the second point, (1,7). Connect the plotted points with the ruler.
Tldr; Plot a point at (0,4) because the y intercept is +4, plot a point at (1,7) because the slope is 3/1, and use a ruler to connect the two points in a line.
No. of students playing at least one game = 44
Step-by-step explanation:
B = basketball; V = volleyball
n(B) = no of students playing only B
n(V) = no. of students playing only V
n(B∩V) = no. of students playing both B and V
Now:
32 students play basketball. Some of them could also be playing volleyball. Hence, the number of students playing only basketball will be 32 minus those that play both.
n(B) = 32 - 13 ............(Given that 13 play both games)
n(B) = 19
Similarly,
25 students play volleyball. Some of them could also be playing basketball. Hence, the number of students playing only volleyball will be 25 minus those that play both.
n(V) = 25 - 13
n(V) = 12
Thus, we have 19 students playing only B, 12 students playing only V and 13 students playing BOTH.
Clearly, the number of students that play at least one game is:
No. of students playing ONLY basketball +
No. of students playing ONLY volleyball +
No. of students playing BOTH
This can be given as:
n(B) + n(V) + n(B∩V)
= 19 + 12 + 13
= 44