The range of the function is 
Explanation:
The function is 
The domain of the function is 
We need to find the range of the function.
The range can be determined by substituting the values of domain in the function.
Thus, the range of the function when the domain is -3 is given by



Thus, the range is -19 when 
The range of the function when the domain is 0 is given by



Thus, the range is -4 when 
The range of the function when the domain is 4 is given by



Thus, the range is 16 when 
Thus, the range of the function is
when their corresponding domain is 
Arranging the range in order from least to greatest is given by

Hence, the range of the function is 
<span>1/2x+3y/4=5 => (1/2)x + (3/4)y = 5
1/5x+3y/2=2 => (1/5)x + (3/2)y = 2
Eliminate the fractional coefficients: Mult. the first equation by 4 and mult. the second equation by 10:
2x + 15y = 20
</span><span>Multiply the 1st equation by -1:
-</span>2x - 3y = -20
2x + 15y = 20
-------------------
12y = 0, so y = 0. Then the first equation becomes 2x + 3(0) = 20, or
x=10.
Solution is (10,0).
Answer:
The Possible dimension of the ring could be;
20 ft × 60 ft
25 ft × 48 ft
30 ft × 40 ft
60 ft × 20 ft
48 ft × 25 ft
40 ft × 30 ft
Step-by-step explanation:
Given:
Number of skaters = 30
Area for each skater = 40 sq ft
We need to find the dimension of rectangular ring the are going to build.
Now we know that they building the skating ring such that they all can use at same time.
Hence if the all use at same time then we will find the total area first.
Total area can be calculated by multiplying Number of skaters with area required for each skaters.
Framing the equation we get;
Total area = 
Hence The total area of the rectangular ring would be 1200 sq. ft.
Now we know that Total area is equal to product of length and width.

1200 can be written as = 20 × 60, 25 × 48, 30 × 40,60 × 20,48 × 25,40 × 30
Hence the Possible dimension of the ring could be;
20 ft × 60 ft
25 ft × 48 ft
30 ft × 40 ft
60 ft × 20 ft
48 ft × 25 ft
40 ft × 30 ft
ANSWER
C. 64.29
EXPLANATION
The bigger right triangle is similar to the smaller right triangle, therefore

Multiply both sides by 30;

Simplify


We correct to the nearest hundredthth to obtain,

The correct choice is C.