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3 years ago

HELPPPPpPpPPP BRAINLIESTTTTTT

Mathematics

2 answers:

Sunny_sXe [5.5K]3 years ago

4 0

It’s “C” :))))))))))))$

In-s [12.5K]3 years ago

4 0

Answer:

The correct answer is C

Step-by-step explanation:

because

A). would be x Less than or equal to 8

B). would be x Greater than or equal to 8

C). would be x Greater than 8

D). would be x Less than 8

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A collection of dimes is arranged in a triangular array with 17 coins in the base row, 16 in the next, 15 in the next, and so fo

Crazy boy [7]

Answer:

153 coins will be there.

Step-by-step explanation:

The number of coin in the bottom row / or last row = 17

The number of coins in the second last row = 16

The number of coins in the second row = 2

The number of coins in the first row = 1

So the total number of coins = (Number of coin in the first row) + (Number of coins in the second row) + (Number of coins in the third row) + ....... + (Number of coins in the last row / seventeenth row)

Total number of coins = 1+2+3+....+16+17

Total number of coins = $\frac{17\times(17+1)}{2}=\frac{17\times18}{2}=17\times9=153$

(NOTE: Sum of first n natural number = $\frac{\boldmath n\times(n+1)}{2}$ )

7 0

3 years ago

G-10+7g=15+3g I keep reworking it and I keep getting the wrong answer, please help

Ludmilka [50]

First you need to combine like terms the get all numbers and leters to one side then divide to get g alone so your left with G=5

5 0

3 years ago

Read 2 more answers

Adam has 10 blocks numbered 1 through 10. Which describes the probability of randomly choosing a block that has an even number?

Licemer1 [7]

Answer:

$\dfrac{1}{2}$

Step-by-step explanation:

Given that:

10 number of blocks which have numbers from 1 through 10.

To find:

Probability of randomly choosing a block that has an even number.

Solution:

The given set of numbers is: {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

There are a total of 5 Even numbers are {2, 4, 6, 8, 10}.

And There are a total of 5 Odd number are {1, 3, 5, 7, 9}.

Formula for probability of an event <em>E</em> can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

Here, Event <em>E </em>is randomly choosing an even number.

Number of favorable cases = 5

Total number of cases = 10

Therefore, the required probability is:

$P(E) = \dfrac{5}{10}\\\Rightarrow P(E) = \dfrac{1}{2}$

3 0

2 years ago

What is one thousandth less than 0.029

goblinko [34]

Answer:

0.0009

Step-by-step explanation:

8 0

3 years ago

Help please and thanks

STALIN [3.7K]

Answer:

Rate of change of length of shadow is $\frac{15}{7} ft/s$

Step-by-step explanation:

Consider the figure

We have

$\begin{aligned}&\frac{d x}{d t}=\text { rate of person walking } \\&\frac{d y}{d t}=\text { rate of change of shadow length } \\&\frac{d x}{d t}+\frac{d y}{d t}=\text { rate of change of tip of shadow }\end{aligned}$

$\begin{aligned}&\frac{6}{20}=\frac{y}{x+y} \\&6(x+y)=20 y \\&6 x+6 y=20 y \\&6 x=14 y\end{aligned}$

$6\left(\frac{d x}{d t}\right)=14\left(\frac{d y}{d t}\right)\\\\6(5)=14\left(\frac{d y}{d t}\right)\\\\\frac{30}{14}=\frac{d y}{d t}\\\\\frac{15}{7}=\frac{d y}{d t}\\\\$

Rate of change of length of shadow is $\frac{15}{7} ft/s$

8 0

2 years ago