Answer:
y = -3/2x + 5/2
Step-by-step explanation:
Point: (5, -5)
Parallel to: y = -3/2x + 2
Slope= -3/2 (parallel lines have the same slope)
y-intercept = -5 - (-3/2)(5) (y - slope times x) =
-5 + 15/2 = 5/2
Point-slope form: y-y1 = m(x-x1)
Standard form: ax + by = c
Slope-intercept form: y = mx+b
Start by finding the slope. We know it is negative since the line is decreasing. The slope is -4/3.
To create point-slope form, we need to get one point from the graph. Let's use (3,0).
To create slope-intercept form, we need the slope and the y-intercept. The y-intercept is the point where our equation crosses the y-axis. For this equation, it is 4.
To get standard form, solve the equation in terms of C.
Point-slope form: y = -4/3(x-3)
Slope-intercept form: y = -4/3x + 4
Standard form: 4/3x + y = 4
Step-by-step explanation:
this creates a right-angled triangle.
the right angle (90°) being the angle between flag pole and ground.
the angle ground-wire is 50°.
because we know that the sum of all angles in a triangle is always 180°, we know then that the angle flagpole-wire is
180 - 90 - 50 = 40°
so, we have the situation to know 1 side and all angles.
to get the other sides we use best the law of sine :
a/sin(A) = b/sin(B) = c/sin(C)
where the sides and related angles are always opposite of each other.
in our case now we have
24/sin(50) = wire/sin(90) = wire/1 = wire = 31.32977494... ft
so, the rounded answer is that the wire must be
31.3 ft long
Answer:
Step-by-step explanation:
Step-by-step explanation:
Gradient of line AB = 6/2 = 3.
Gradient of line CD = 10/2 = 5.
Gradient of line AD = 12/8 = 1.5.
