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gogolik [260]
3 years ago
11

Which are true or false

Mathematics
1 answer:
Savatey [412]3 years ago
5 0

we are given

y=19.75x

Here,

y is the number of gallons of water in the pool

x is the number of minutes the truck has been filing the pool

now, we will verify each options

option-A:

When x=1

then y=19.75

so, for 1 minute , number gallons =19.75

so, this is FALSE

option-B:

Since, we have

y=19.75x

It is similar to equation of line

y=mx+b

But b=0

It means that it passes through origin

so, this is TRUE

option-C:

y=19.75x

we can compare it with

y=mx

where m is the rate

so, we get

m=19.75

while we are given

the water in swimming pool increase about 100 gallons by every 5 minutes

so, we get rate as

m=\frac{100}{5} =20 gallons per minute

this is close to 19.75

so, they are approximately equal

so, this is TRUE

option-d:

x-value and y-value will show relationship

and ratio will always be constant or equivalent

because it has linear relationship

so, this is TRUE

option-e:

We need to check

(8,150) ..so, x=8 and y=150

we can plug this in our equation

and we get

150=19.75\times 8

150=158

Since, left side is not equal to right side

so, this can not be point

so, this is FALSE


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Angelina_Jolie [31]

Answer:

A5#A

Step-by-step explanation:

5 0
2 years ago
I can't figure out how to do (i + j) x (i x j)for vector calc
Vinil7 [7]

In three dimensions, the cross product of two vectors is defined as shown below

\begin{gathered} \vec{A}=a_1\hat{i}+a_2\hat{j}+a_3\hat{k} \\ \vec{B}=b_1\hat{i}+b_2\hat{j}+b_3\hat{k} \\ \Rightarrow\vec{A}\times\vec{B}=\det (\begin{bmatrix}{\hat{i}} & {\hat{j}} & {\hat{k}} \\ {a_1} & {a_2} & {a_3} \\ {b_1} & {b_2} & {b_3}\end{bmatrix}) \end{gathered}

Then, solving the determinant

\Rightarrow\vec{A}\times\vec{B}=(a_2b_3-b_2a_3)\hat{i}+(b_1a_3+a_1b_3)\hat{j}+(a_1b_2-b_1a_2)\hat{k}

In our case,

\begin{gathered} (\hat{i}+\hat{j})=1\hat{i}+1\hat{j}+0\hat{k} \\ \text{and} \\ (\hat{i}\times\hat{j})=(1,0,0)\times(0,1,0)=(0)\hat{i}+(0)\hat{j}+(1-0)\hat{k}=\hat{k} \\ \Rightarrow(\hat{i}\times\hat{j})=\hat{k} \end{gathered}

Where we used the formula for AxB to calculate ixj.

Finally,

\begin{gathered} (\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=(1,1,0)\times(0,0,1) \\ =(1\cdot1-0\cdot0)\hat{i}+(0\cdot0-1\cdot1)\hat{j}+(1\cdot0-0\cdot1)\hat{k} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=1\hat{i}-1\hat{j} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=\hat{i}-\hat{j} \end{gathered}

Thus, (i+j)x(ixj)=i-j

8 0
1 year ago
Which equation does NOT represent a proportional relationship between two variables with the constant of proportinality of? 1/2
Dimas [21]

Answer:

(D) y=x+\frac{1}{2}

Step-by-step explanation:

Two variables x and y are proportionally related  if they can be written in the form y=kx, where k is the constant of proportionality.

From the given options, if k=\frac{1}{2}

(B)y=\frac{1}{2}x is of the form y=kx

(C)y=\frac{3}{6}x is of the form y=kx with k=\frac{1}{2} as \frac{3}{6}=\frac{1}{2} in its lowest form.

(C)y=0.5x is of the form y=kx with k=\frac{1}{2} as 0.5=\frac{1}{2} in fractional form.

On the Contrary,

In Option D, y=x+\frac{1}{2} does not represent a proportional relationship between x and y. The constant of proportion is supposed to be a product of x.

6 0
3 years ago
What is the measure of the missing angle
Likurg_2 [28]

Answer:

45 degrees xxxxxxxxxx

Step-by-step explanation:

simple geo

3 0
3 years ago
Cameron drives a semitruck for Haulin' Harry's Trucking Company. He earns $0.45 for every mile he drives. If Cameron drove 827.4
ANEK [815]

Answer:

$372.330

Step-by-step explanation:

if 1 mile = $0.45 and you want to find out 827.4 miles

you should multiple $0.45 × 872.4

1 mile : $0.45

827.4 × $0.45 = 372330

827.4 : $372.330

3 0
3 years ago
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