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gogolik [260]
3 years ago
11

Which are true or false

Mathematics
1 answer:
Savatey [412]3 years ago
5 0

we are given

y=19.75x

Here,

y is the number of gallons of water in the pool

x is the number of minutes the truck has been filing the pool

now, we will verify each options

option-A:

When x=1

then y=19.75

so, for 1 minute , number gallons =19.75

so, this is FALSE

option-B:

Since, we have

y=19.75x

It is similar to equation of line

y=mx+b

But b=0

It means that it passes through origin

so, this is TRUE

option-C:

y=19.75x

we can compare it with

y=mx

where m is the rate

so, we get

m=19.75

while we are given

the water in swimming pool increase about 100 gallons by every 5 minutes

so, we get rate as

m=\frac{100}{5} =20 gallons per minute

this is close to 19.75

so, they are approximately equal

so, this is TRUE

option-d:

x-value and y-value will show relationship

and ratio will always be constant or equivalent

because it has linear relationship

so, this is TRUE

option-e:

We need to check

(8,150) ..so, x=8 and y=150

we can plug this in our equation

and we get

150=19.75\times 8

150=158

Since, left side is not equal to right side

so, this can not be point

so, this is FALSE


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X-4y=28 2x+y=2 Elimination
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3 years ago
To graduate this semester, you must pass Statistics 314; and you estimate that you have an 85% chance of passing. You need to pa
Nitella [24]

Answer:

Probability of graduating this semester is 0.7344

Step-by-step explanation:

Given the data in the question;

let A represent passing STAT-314

B represent passing at least in MATH-272 or MATH-444

M1 represent passing in MATH-272

M2 represent passing in MATH-444

C represent  passing GERMAN-32

now

P( A ) = 0.85, P( C ) = 90, P( M1 ) = P( M2 ) = 0.8

P( B ) = P( pass at least one of either MATH-272 or MATH-444 ) = P( pass in MATH-272 but not MATH-444 ) + ( pass in MATH-444 but not in MATH 272) + P( pass both )

P( B ) =  P( M1 ) × ( 1 - P( M2 ) ) + ( 1 - P( M1 ) ) × P( M2 ) + P( M1 ) × P( M2 )

we substitute

⇒ 0.8×0.2 + 0.2×0.8 + 0.8×0.8 = 0.16 + 0.16 + 0.64 = 0.96

∴ the probability of graduating this semester will be;

⇒ P( A ) × P( B ) × P( C )

we substitute

⇒ 0.85 × 0.96 × 90

⇒ 0.7344

Probability of graduating this semester is 0.7344

6 0
3 years ago
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