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Lerok [7]
3 years ago
14

-5(3m+6)=-3(4m-2) and -7(k+9)=9(k-5)-14k show work please those are two diffrent questions

Mathematics
2 answers:
zzz [600]3 years ago
5 0
First One: 
-5(3m+6)=-3(4m-2)
-15m-30 = -12m+6
-3m = 36
m = -12

Second:
-7(k+9)=9(k-5)-14k
-7k-63 = 9k-45-14k
-7k-63=-5k-45
-2k=18
k=-9
Deffense [45]3 years ago
4 0
1.   -5(3m+6) = -3(4m-2)

We must open the parenthesis and multiply every term inside the parenthesis by the number outside the parenthesis so :

   -5*3m - 5*6 = -3*4m - 3*(-2)

   -15m - 30 = -12m +6   | +12m 

   -15m +12m -30 = 12m+12m + 6

   -3m - 30 = 6  | +30
    -3m - 30 + 30  = 6+30

   -3m = 36 

   m = -36÷3

   m = -12




2.   <span>-7(k+9)=9(k-5)-14k
</span>

Here we'll do the same thing : 
 
   -7*k - 7*9 = 9*k - 9*5 - 14k 

   -7k - 63 = 9k - 45 -14k 

   -7k - 63 = - 5k - 45 |  + 5k
 
   -7k+5k -63 = -5k + 5k - 45

   -2k - 63 = - 45 | + 63

   -2k - 63 + 63 = -45 + 63

         -2k =  18 


           k = -18÷2

          k = -9
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Step-by-step explanation:

According to the Question,

  • Given, A theater has 56 rows of seats. If there are 13 seats in the first row, 18 in the 2nd row, 23 in the 3rd row.

We have a number sequence  13, 18, 23, ...

  • We can say that this is an arithmetic sequence because of the common difference 'd', is equal to 5, and the first term 'a1' is equal to 13.
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Substitute the given values into the equation to solve for the sum of the 56 rows of seats.

S_56= \frac{56}{2}[2(13)+(56-1)(5)]\\S_{56}=28\left[26+275\right]\\S_{56}=28\left[301\right]\\S_{56}=8428

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4 0
3 years ago
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Step-by-step explanation:

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