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Monica [59]
3 years ago
6

Given cos t = 1/2 tan 0 find sin (t) and sec (t)

Mathematics
1 answer:
777dan777 [17]3 years ago
3 0

Answer:

Sin(t) =  \frac{\sqrt{3} }{2} } and sec(t) =2

Step-by-step explanation:

The secant function is the reciprocal function of the cosine function. Therefore, given that sec(t) = \frac{1}{cos(t)} then, if  cos(t) = \frac{1}{2} then  sec(t) =2.

On the other hand, if cos (t) = 1/2 ⇒ t = ±\frac{\pi}{3}

Then, the sin(\frac{\pi}{3}) = \frac{\sqrt{3} }{2} }

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Which expression is equivalent to 5^3?
AleksAgata [21]

Answer:

C and D

Step-by-step explanation:

5^3 - 5^0 = 125 - 1 = 124, so it's not A

5^12 / 5^4 = 5^(12-4) = 5^8, so it's not B

5^7 * 5^-4 = 5^(7+(-4)) = 5^3, so it can be C

5^0 * 5^3 = 5^(0+3) = 5^3, so it can be D

5 + 5^2 = 5 + 25 = 30, so it can't be E

3 0
2 years ago
What simple interest rate would allow $6000 to grow to an amount of $14550 in 10 years?
Harman [31]

Answer:

\boxed{ \bold{ \huge{  \boxed{ \sf{ \: 14.25 \: \% \: }}}}}

Step-by-step explanation:

Given,

Principal ( P ) = $ 6000

Amount ( A ) = $ 14550

Time ( T ) = 10 years

Rate ( R ) = ?

<u>Finding </u><u>the </u><u>Interest</u>

The sum of principal and interest is called an amount.

From the definition,

\boxed{ \sf{Amount =  \: Principal + Interest}}

plug the values

⇒\sf{14550 = 6000 + Interest}

Swap the sides of the equation

⇒\sf{6000 + Interest = 14550}

Move 6000 to right hand side and change its sign

⇒\sf{Interest = 14550 - 6000}

Subtract 6000 from 14550

⇒\sf{Interest = \: 8550 \: }

Interest = $ 8550

<u>Finding </u><u>the </u><u>rate </u>

{ \boxed{ \sf{Rate =  \frac{Interest \times 100}{Principal \times Time}}}}

plug the values

⇒\sf{ Rate = \frac{8550  \times 100}{6000 \times 10} }

Calculate

⇒\sf{Rate =  \frac{855000}{60000} }

⇒\sf{Rate = 14.25 \: \% \: }

Hope I helped!

Best regards!!

8 0
3 years ago
PLEASE HELPPPPPPPPPPPPPP
gregori [183]

Answer:

False

Step-by-step explanation:

To find the inverse of a function, switch the variables and solve for y.

The inverse of f(n)=-(n+1)^3:

y=-(n+1)^3

n=-(y+1)^3

\sqrt[3]{n} =-(y+1)

\sqrt[3]{n} =-y-1

\sqrt[3]{n} +1=-y-(\sqrt[3]{n} +1)=y

-\sqrt[3]{n} -1=y

5 0
3 years ago
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What is 1,500mm + 15mm + 5m =
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1,520
add 1,500 plus 15 plus 5
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