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zimovet [89]
3 years ago
8

Please help. I need to find the Slope and identify the type of Slope. I already know the type. (Number 11)

Mathematics
1 answer:
Mamont248 [21]3 years ago
5 0

slope = 0

hope this helps!

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The claim that 40% of those persons who retired from an industrial job before the age of 60 would return to work if a suitable j
Bad White [126]

Answer:

The p-value of the test is of 0.1922 > 0.02, which means that there is not significant evidence to reject the null hypothesis, that is, there is not significant evidence to conclude that the proportion is of less than 40%.

Step-by-step explanation:

Test if the proportion is less than 40%:

At the null hypothesis, we test if the proportion is of at least 0.4, that is:

H_0: p \geq 0.4

At the alternative hypothesis, we test if the proportion is of less than 0.4, that is:

H_1: p < 0.4

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.4 is tested at the null hypothesis:

This means that \mu = 0.4, \sigma = \sqrt{0.4*0.6}

74 out of the 200 workers sampled said they would return to work

This means that n = 200, X = \frac{74}{200} = 0.37

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.37 - 0.4}{\frac{\sqrt{0.4*0.6}}{\sqrt{200}}}

z = -0.87

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion below 0.37, which is the p-value of z = -0.87.

Looking at the z-table, z = -0.87 has a p-value of 0.1922.

The p-value of the test is of 0.1922 > 0.02, which means that there is not significant evidence to reject the null hypothesis, that is, there is not significant evidence to conclude that the proportion is of less than 40%.

7 0
2 years ago
A company will lease office space in win buildings the annual cost is 21.75 per square foot in the first building and 17 per squ
brilliants [131]
What is your question?
I cannot see it
5 0
3 years ago
Question : In the given figure , ∆ APB and ∆ AQC are equilateral triangles. Prove that PC = BQ.
lorasvet [3.4K]

Answer:

See Below.

Step-by-step explanation:

We are given that ΔAPB and ΔAQC are equilateral triangles.

And we want to prove that PC = BQ.

Since ΔAPB and ΔAQC are equilateral triangles, this means that:

PA\cong AB\cong BP\text{ and } QA\cong AC\cong CQ

Likewise:

\angle P\cong \angle PAB\cong \angle ABP\cong Q\cong \angle QAC\cong\angle ACQ

Since they all measure 60°.

Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:

m\angle PAC=m\angle PAB+m\angle BAC

Likewise:

m\angle QAB=m\angle QAC+m\angle BAC

Since ∠QAC ≅ ∠PAB:

m\angle PAC=m\angle QAC+m\angle BAC

And by substitution:

m\angle PAC=m\angle QAB

Thus:

\angle PAC\cong \angle QAB

Then by SAS Congruence:

\Delta PAC\cong \Delta BAQ

And by CPCTC:

PC\cong BQ

5 0
3 years ago
Read 2 more answers
What is the slope of the line?
Sav [38]

Answer:

Slope: 3

Step-by-step explanation:

find 2 points on the line and do rise/run which would get 3/1 which is 3

6 0
3 years ago
What is the elimination to this solution i think its b
Blababa [14]

EXPLANATION:

To get the solution of the simultaneous equation, using the elimination method:

We will have the following steps:

Step 1:

Write the two equations:

\begin{gathered} y=-\frac{1}{2}x+3 \\ y=-\frac{7}{2}x-3 \end{gathered}

Step2: Subtract the two equations:

\begin{gathered} y-y=-\frac{1}{2}x-(-\frac{7}{2}x)+3-(-3) \\ 0=-\frac{1}{2}x+\frac{7}{2}x+6 \\  \end{gathered}

Step 3: Simplify the expression

\begin{gathered} 0=3x+6 \\ 3x=-6 \\ x=-\frac{6}{3} \\ x=-2 \end{gathered}

Step 4: Substitute x=-2 into the formula:

\begin{gathered} y=-\frac{1}{2}x+3 \\ y=-\frac{1}{2}\times-2+3 \\ y=1+3 \\ y=4 \end{gathered}

Therefore, the answer is

(-2,4)

Thus,

Option B is correct

5 0
1 year ago
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