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katrin2010 [14]
3 years ago
9

Study was conducted to determine the mean birth weight of a certain breed of kittens, Consider the birth weights of kittens to b

e
normally distributad. A sample of 45 kittens was randomly selected from all kittens of this breed at a large veterinary hospital. The
waight of each kitten in the sample was recorded. The sample mean was 3.
56 ounces, and the sample standard deviation was 0.2 our
What is the margin of error for a 90% confidencelinterval on the mean birth weight of all kittens of this breed,
tpoint
Mathematics
1 answer:
ikadub [295]3 years ago
5 0

Answer:

(see picture)

hoping this helps

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<img src="https://tex.z-dn.net/?f=7%20%7Bx%7D%5E%7B3%7D%20%20%2B%204x%20-%205%20%2B%208%20%7Bx%7D%5E%7B5%7D%20" id="TexFormula1"
elixir [45]

Answer:

D

Step-by-step explanation:

The degree of a polynomial is determined by the largest exponent of a term within the polynomial.

Given

7x³ + 4x - 5 + 8x^{5}

The term with the largest exponent is 8x^{5} with exponent 5

Thus the polynomial is of degree 5 → D

3 0
3 years ago
Increase £15837.77 by 18.5%
labwork [276]

if we take £15837.77 to be the 100% and we increase it by 18.5%, that'll be 100% + 18.5% = 118.5%.

\begin{array}{ccll} \pounds&\%\\ \cline{1-2} 15837.77 & 100\\ x& 118.5 \end{array} \implies \cfrac{15837.77}{x}=\cfrac{100}{118.5} \implies (15837.77)(118.5)=100x \\\\\\ \cfrac{(15837.77)(118.5)}{100}=x\implies 18767.76\approx x

6 0
2 years ago
Help please no links or I’ll report
vfiekz [6]

Answer. the answer for the problem you asked is A

8 0
2 years ago
a) find center of mass of a solid of constant density bounded below by the paraboloid z=x^2+y^2 and above by the plane z=4.(b) F
slava [35]

Answer: x-bar = y-bar = 0 whereas z-bar = 8/3

               M= (c^2)/8 which is intern equal to 2\sqrt{2}

Step-by-step explanation:

           Find the area, by setting the limits as

               = 4\cdot \int _0^{\frac{\pi }{2}}\int _0^2\int _{r^2}^4\:rdzdrd\theta

                =4\cdot \int _0^{\frac{\pi }{2}}\int _0^2r\cdot \:4-r^3drd\theta

                =4\cdot \int _0^{\frac{\pi }{2}}4d\theta

                 =8\pi

Therefore;

Mxy=  \int _0^{2\pi }\int _0^2\int _{r^2}^4\:zrdzdrd\theta

       z-bar = 8/3

M= 8\pi dividing it into two volume gives us = 4\pi

means  4\pi =\int _0^{2\pi }\int _0^{\sqrt{c}}\int _r^c\:rdzdrd\theta

             4\pi =\left(\pi c^2-2\pi \frac{c^{\frac{3}{2}}}{3}\right)

              c=2\sqrt{2}

       

                 

                 

5 0
3 years ago
Simplify the expression. . 1 V 3.0 2​
Vlad [161]

Answer:

81x^4/16  (81x to the fourth over 16)

Step-by-step explanation:

First you apply the exponent rule: (a/b)^c  ->  a^c/b^c

So it looks like this: 3x^2/4^2

Then you apply the exponent to the whole thing, and 3^4 is 81, x^4 stays like that, and 2^4 is 16

You can't simplify any more after that so that's your answer

Hope this helps!

5 0
3 years ago
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