What is the linear cycle?

Gps receivers are commonly used by individuals to determine their geographic location while hiking and to obtain driving directi

soldier1979 [14.2K]

I think it is true also.

7 0

3 years ago

What how do i delete a question

Dvinal [7]

Answer: not sure if you can

Explanation: idk if you can but if you wanna get a good answer try searching up on google hope i helped!

7 0

3 years ago

Consider the following code snippet:public static void main(String[] args) throws FileNotFoundExceptionWhich of the following st

iVinArrow [24]

Answer:

The main method should simply terminate if the FileNotFoundException occurs.

Explanation:

Considering the full code snippet

snippet:public static void main(String[] args) throws FileNotFoundException

public static void main(String[])

represent the entry point method to a java main method

The addition of

throws FileNotFoundException

widens the scope of the main method to explicitly specifies that an exception named the FileNotFoundException may be thrown.

So, if any part of the code explicitly throws the FileNotFoundException the compiler makes use of this to throw an exception.

By throwing an exception, the main method is not catching any exceptions, instead it handles the FileNotFoundException by throwing it to the source which invoked the main method

This is required by the compiler to terminate the program if the FileNotFoundException occurs.

8 0

3 years ago

You are testing a site and realize that when you click a graphic link you see an outline but no picture. What is wrong with the

deff fn [24]

Pictures not loading on websites Chrome – Many users reported that pictures aren't loading on websites in Chrome. To fix the problem, be sure to check your Chrome settings and disable your antivirus. Images won't load in Chrome – Sometimes this issue can appear if JavaScript is disabled in your browser.

Explanation:

Speaking of image problems, users reported the following issues:

Broken image icon Firefox, Internet Explorer – According to users, you might be able to experience this issue in other browsers including Firefox and Internet Explorer. If the problem appears in other browsers, the issue is related to your system or to your network configuration.
Pictures not loading on websites Chrome – Many users reported that pictures aren’t loading on websites in Chrome. To fix the problem, be sure to check your Chrome settings and disable your antivirus.
Images won’t load in Chrome – Sometimes this issue can appear if JavaScript is disabled in your browser. If that’s the case, simply enable JavaScript and the problem will be resolved.
Chrome showing broken images – In some cases, extensions can lead to this problem, and if you noticed that your images are missing, simply disable or uninstall your extensions and check if that solves the problem.
You can remove an image from the preview by clicking the thumbnail below Available images. Edit Descriptions: If you've added multiple images, click the description below each image in the preview to edit it.
Icon in the top-right corner of the window. Select Internet Options. In the Internet Options window, click the Advanced tab. In the Settings under Multimedia, make sure there is a check in the Show Pictures check box.

7 0

3 years ago

There are n poor college students who are renting two houses. For every pair of students pi and pj , the function d(pi , pj ) ou

Nuetrik [128]

Answer:

Here the given problem is modeled as a Graph problem.

Explanation:

Input:- n, k and the function d(pi,pj) which outputs an integer between 1 and n2

Algorithm:-We model each student as a node. So, there would be n nodes. We make a foothold between two nodes u and v (where u and v denote the scholars pu and pv respectively) iff d(pu,pv) > k. Now, Let's call the graph G(V, E) where V is that the vertex set of the graph ( total vertices = n which is that the number of students), and E is that the edge set of the graph ( where two nodes have edges between them if and only the drama between them is bigger than k).

We now need to partition the nodes of the graph into two sets S1 and S2 such each node belongs to precisely one set and there's no edge between the nodes within the same set (if there's a foothold between any two nodes within the same set then meaning that the drama between them exceeds k which isn't allowed). S1 and S2 correspond to the partition of scholars into two buses.

The above formulation is akin to finding out if the graph G(V,E) is a bipartite graph. If the Graph G(V, E) is bipartite then we have a partition of the students into sets such that the total drama <= k else such a partition doesn't exist.

Now, finding whether a graph is bipartite or not is often found using BFS (Breadth First algorithm) in O(V+E) time. Since V = n and E = O(n2) , the worst-case time complexity of the BFS algorithm is O(n2). The pseudo-code is given as

PseudoCode:

// Input = n,k and a function d(pi,pj)

// Edges of a graph are represented as an adjacency list

1. Make V as a vertex set of n nodes.

2. for each vertex u ∈ V

$\rightarrow$ for each vertex v ∈ V

$\rightarrow\rightarrow$ if( d(pu, pj) > k )

$\rightarrow\rightarrow\rightarrow$ add vertex u to Adj[v] // Adj[v] represents adjacency list of v

$\rightarrow\rightarrow\rightarrow$ add vertex v to Adj[u] // Adj[u] represents adjacency list of u

3. bool visited[n] // visited[i] = true if the vertex i has been visited during BFS else false

4. for each vertex u ∈ V

$\rightarrow$ visited[u] = false

5. color[n] // color[i] is binary number used for 2-coloring the graph

6. for each vertex u ∈ V

$\rightarrow$ if ( visited[u] == false)

$\rightarrow\rightarrow$ color[u] = 0;

$\rightarrow\rightarrow$ isbipartite = BFS(G,u,color,visited) // if the vertices reachable from u form a bipartite graph, it returns true

$\rightarrow\rightarrow$ if (isbipartite == false)

$\rightarrow\rightarrow\rightarrow$ print " No solution exists "

$\rightarrow\rightarrow\rightarrow$ exit(0)

7. for each vertex u ∈V

$\rightarrow$ if (color[u] == 0 )

$\rightarrow\rightarrow$ print " Student u is assigned Bus 1"

$\rightarrow$ else

$\rightarrow\rightarrow$ print " Student v is assigned Bus 2"

BFS(G,s,color,visited)

1. color[s] = 0

2. visited[s] = true

3. Q = Ф // Q is a priority Queue

4. Q.push(s)

5. while Q != Ф {

$\rightarrow$ u = Q.pop()

$\rightarrow$ for each vertex v ∈ Adj[u]

$\rightarrow\rightarrow$ if (visited[v] == false)

$\rightarrow\rightarrow\rightarrow$ color[v] = (color[u] + 1) % 2

$\rightarrow\rightarrow\rightarrow$ visited[v] = true

$\rightarrow\rightarrow\rightarrow$ Q.push(v)

$\rightarrow\rightarrow$ else

$\rightarrow\rightarrow\rightarrow$ if (color[u] == color[v])

$\rightarrow\rightarrow\rightarrow\rightarrow$ return false // vertex u and v had been assigned the same color so the graph is not bipartite

}

6. return true

3 0

3 years ago

What is the linear cycle? ​

What is the linear cycle?