Answer: Option B
Step-by-step explanation:
An increased rate of growth refers to exponential growth.
Are those of the form "An amount X increases by a 10% every year"
Then, if in year 0 you have X
in year 1 you have X + 0.1*X = X*1.1
in year 2 you have (X*1.1) + (X*1.1)*0.1 = X*1.1*1,1 = X*1.1^2
and in year n, you have X*1.1^n
Then, an increasing rate of growth is usually described by a number bigger than 1 potentiated by the variable; in this case, the correct option is option b:
h(x)=99(1.05)^x
(where the sign ^ is missing in the question)
