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3 years ago

I need help on this

Mathematics

2 answers:

Anna35 [415]3 years ago

5 0

Answer:

Hi ma bruddah

Step-by-step explanation:

Hi - ma - bru/dd/ah

statuscvo [17]3 years ago

3 0

Answer:

Since it says no more than and d doesn't have that sign so yes hope this helps :D

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Write the equation of the line that passes through the point(-6,12) and is parallel to the line y=8

Ugo [173]

Answer:

y = 12

Step-by-step explanation:

y = 8 is the equation of a horizontal line, parallel to the x- axis.

Thus a parallel line will also be horizontal.

The equation of a horizontal line is

y = c

where c is the y- coordinates of the points it passes through.

The line passes through (- 6, 12) with y- coordinate of 12, thus

y = 12 ← equation of parallel line

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3 years ago

In AFGH, f = 3.1 inches, g = 2 inches and h=3.2 inches. Find the measure of ZF to the

kicyunya [14]

Answer:

68.8

Step-by-step explanation:

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2 years ago

PLEASE HELP ASAP

maria [59]

Answer:

First option: $3x^2-5x=-8$

Second option: $2x^2=6x-5$

Fourth option: $-x^2-10x=34$

Step-by-step explanation:

Rewrite each equation in the form $ax^2+bx+c=0$ and then use the Discriminant formula for each equation. This is:

$D=b^2-4ac$

1) For $3x^2-5x=-8$ :

$3x^2-5x+8=0$

Then:

$D=(-5)^2-4(3)(8)=-71$

Since $D$ this equation has no real solutions, but has two complex solutions.

2) For $2x^2=6x-5$ :

$2x^2-6x+5=0$

Then:

$D=(-6)^2-4(2)(5)=-4$

Since $D$ this equation has no real solutions, but has two complex solutions.

3) For $12x=9x^2+4$ :

$9x^2-12x+4=0$

Then:

$D=(-12)^2-4(9)(4)=0$

Since $D=0$ this equation has one real solution.

4) For $-x^2-10x=34$ :

$-x^2-10x-34=0$

Then:

$D=(-10)^2-4(-1)(-34)=-36$

Since $D$ , this equation has no real solutions, but has two complex solutions.

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3 years ago

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3 years ago

a florist sold bouquets of flowers of red roses to 15 of the first 20 customers who came into his shop. What is the experimental

Paladinen [302]

So I divided. 120 by 15 and got 8. I then multiplied it by 20 and got 160 bouquets

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3 years ago

I need help on this ​

I need help on this