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Elina [12.6K]
3 years ago
14

The diameter and height of a cylinder are equivalent to the edge lengths of a cube. which figure has a greater volume?

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
4 0
The cube. The cylinder clearly fits in the cube, so it has a smaller volume.
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Find the distance of the line segment joining the two points (-4 /2 - /12) and (/32, 2/3)
astraxan [27]

Answer: 4\sqrt{3} .

Step-by-step explanation:

Distance formula : Distance between points (a,b) and (c,d) is given by :-

D=\sqrt{(d-b)^2+(b-a)^2}

Distance between points (-4\sqrt{2},\sqrt{12}) \text{ and }(-\sqrt{32}, 2\sqrt{3}).

D=\sqrt{(2\sqrt{3}-(-\sqrt{12}))^2+(-\sqrt{32}-(-4\sqrt{2}))}\\\\=\sqrt{(2\sqrt{3}+\sqrt{2\times2\times3})^2+(-\sqrt{4\times4\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}-\sqrt{2^2\times3})^2+(-\sqrt{4^2\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}+2\sqrt{3})^2+(-4\sqrt{2}+4\sqrt{2})^2}\\\\=\sqrt{(4\sqrt{3})^2+0}\\\\=4\sqrt{3}\text{ units}

Hence, the correct option is 4\sqrt{3} .

3 0
3 years ago
A watering can dispenses water at the rate of 0.3 gallon per minute. The original volume of water in the can was 7 gallons. Whic
Rudiy27

Answer:

A. {(1, 6.7), (2, 6.4), (3, 6.1)}

Step-by-step explanation:

The watering can dispenses water at a rate of 0.3 gallon per minute and the original volume of water in the can was 7 gallons.

Let y represent the volume of water in the can in gallons

Let x represent time in minutes

f(x) = y = 7 – 0.3(x)

When x = 1,

y = 7 – 0.3(1)

= 7 – 0.3

= 6.7

The pair will be (1, 6.7)

When x = 2,

y = 7 – 0.3(2)

= 7 – 0.6

= 6.4

The pair will be (2, 6.4)

When x = 3,

y = 7 – 0.3(3)

= 7 – 0.9

= 6.1

The pair will be (3, 6.1)

The set of ordered pairs shows the volume of water in the can in gallons (y) as a function of time in minutes (x) from the first minute after the can starts dispensing water is {(1, 6.7), (2, 6.4), (3, 6.1)}  

4 0
3 years ago
What are the lcm of 4,2,4
Delicious77 [7]

The least common multiple of  2  and  4  is  4 .

Here's a useful hint to keep in mind:
If the smaller number is a factor of the larger number,
then the larger number is the LCM of both of them.



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