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Svetach [21]
2 years ago
9

Given the domain {-1,1,3} and the function f(x)=x2+7. Find the Range of the above function Range=

Mathematics
1 answer:
Svetach [21]2 years ago
4 0

Answer:

21

Step-by-step explanation:

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PLSSSS Plsssss help quick
Neporo4naja [7]

Answer:

(x, y) (1,5.5) , (2,5.75) (3,5.83) (4,5.875) (5,5.9)

Step-by-step explanation:

The x values lie on the horizontal line and the y values lie on the vertical line.

In order to find the value of y you must substitute the value of x in the equation given and you must plot you graph using the answers you got which I wrote for you.

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The elevations, in feet, of three cities are marked on the number line shown below.
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I think the answer it C
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Round<br> 38.86 to 1 decimal place
Sonbull [250]
38.9 is the answer. because it is rounded to the nearest tenth.
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Firdavs [7]

Answer:

$337.5

Step-by-step explanation:

He would get $337.5 because if he gets $11.25 every hour you just multiply $11.25 by 30 hours.

7 0
3 years ago
How to divide (x^2+5x-36)÷(x-4)
mr_godi [17]

Answer:

x + 9

Step-by-step explanation:

Since the divisor is in the form of <em>x - c</em>, use what is called <em>Synthetic Division</em>. Remember, in this formula, -c gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:

4| 1 5 -36

↓ 4 36

----------------

1 9 0 → x + 9

You start by placing the c in the top left corner, then list all the coefficients of your dividend [x² + 5x - 36]. You bring down the original term closest to <em>c</em><em>,</em> then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have NO REMAINDER. Finally, your quotient is one degree less than your dividend, so that 1 in your quotient can be an x, and the 9 follows right behind it, giving you the other factor of x + 9.

If you are ever in need of assistance, do not hesitate to let me know by subscribing to my channel [USERNAME: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.

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3 years ago
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