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2 years ago

Given the domain {-1,1,3} and the function f(x)=x2+7. Find the Range of the above function Range=

Mathematics

1 answer:

Svetach [21]2 years ago

4 0

Answer:

Step-by-step explanation:

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B is between A and C. AB = 3x, BC = 2x + 7, AC = 42<br><br> a) X =<br> b)AB =<br> c)BC=

ryzh [129]

Answer: x=7

ab=21

bc=14

Step-by-step explanation:

ab=3x

bc=2x±7

ac=42

3x±2x±7=42

5x±7=42

5x=42-7

5x=35

to get the value of x you divide 35 by 5x

35÷5x=7

so the value of x is 7

ab=3x

x=7

3x=7×3x

7×3=21

x=7

2x=7×2x

2×7=14

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2 years ago

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NeX [460]

Answer:34 1/2 cubes can fit

Step-by-step explanation: multiply all of them by 2

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2 years ago

What do you think the value of represents in the function? How can you predict what the graph of a quadrati function will look l

allochka39001 [22]

Answer:

Step-by-step explanation:

Parts of the question are missing.

y = a(x-h)² + k is a vertical parabola.

If a is positive, the parabola opens upwards.

If a is negative, the parabola opens downwards.

The vertex is at (h, k)

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2 years ago

3. The cost of a ticket twill be no more than $26.

goblinko [34]

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3 years ago

A and B are two points on square ABCD with coordinates A(1,3) and B(5,3). What are the lengths of the diagonals AC and BD? Round

lilavasa [31]

Answer:

$AC = BD = 5.7$

Step-by-step explanation:

Given

$A = (1,3)$

$B = (5,3)$

Required

The length of the diagonals

First, calculate the length of AB using:

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

So, we have:

$AB = \sqrt{(1 - 5)^2 + (3 - 3)^2}$

$AB = \sqrt{(-4)^2 + 0^2}$

$AB = \sqrt{16}$

$AB = 4$

The diagonal of a square is calculated using:

$Diagonal = x\sqrt{2$

Where x is the length of each side.

So:

$AC = BD = AB\sqrt{2}$

$AC = BD = 4\sqrt{2}$

$AC = BD = 5.7$ -- approximated

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3 years ago