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4 years ago

What is 5.4%of65???!!!

2 answers:

7 0

To find 5.4 percent of 65, first set up your problem. 65 would be our 100%, and we're looking for the value of x. So, 65=100, and x=5.4. Now we can set up an equation of 65 over x = 100 over 5.4. Now you can solve. When solving the equation, you get the answer of 3.51.
3.51 is 5.4% of 65.

goldenfox [79]4 years ago

4 0

The answer is 12.037037037 or rounded the nearest tenth it is 12

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Find x if AB = 9, BC = 2x - 5,<br> and AC = x + 9

Oxana [17]

Answer:

x = 5

Step-by-step explanation:

Using the fact that line segments AB and BC are parts of the whole line segment AC, we can write the following equation:

AB + BC = AC

Now, using the given values, we can substitute in for the equation and solve for x:

AB + BC = AC

9 + 2x - 5 = x + 9

2x + 4 = x + 9

x = 5

Thus, we have found that for these sets of equations for these line segments, our value for x should be 5.

Cheers.

5 0

3 years ago

Read 2 more answers

X fraction 2 - 5 = 25

xxTIMURxx [149]

Answer:

X=60

Step-by-step explanation:

X fraction 2 - 5 = 25

X/2-5=25

X/2 =25+5

X/2=30

X=60

60 is the answer

6 0

3 years ago

Imagine each letter of the word ""mathematical"" is written on individual pieces of paper and placed in a bag. Should you pick a

Aleksandr-060686 [28]

Answer:

The question has a missing part and here it the complete question:

Imagine each letter of the word “Mathematical” is written on individual pieces of paper and placed in a bag. Should you pick a random letter from that bag, what is the probability that you pick a vowel?

Answer: 5/12

Step-by-step explanation:

The question asks for the probability of picking a vowel.

From the word 'Mathematical', we have a total of 12 letters and a total of 5 vowels (a,e,a,i,a).

Probability of picking a vowel = Total number of times the event(vowel) occurs/total number of possible outcomes(total letters)

$Probability = \frac{5}{12}$

6 0

3 years ago

Help me answer this please

Anna007 [38]

Answer:

im pretty sure its B

Step-by-step explanation:

5 0

3 years ago

A one-parameter family of solutions of the DE P' = P( 1 - P) is given below. P = c1et/1 + c1et Does any solution curve pass thro

topjm [15]

Answer:

a. The curve $P(t) = -\frac{6e^t}{5-6e^t}$ passes through the point (0, 6)

b. No solution of the curve $P(t)$ passes through the point (0, 1)

Step-by-step explanation:

Consider the family of the solution of DE $P' = P(1 - P)$ is $P = \frac{c_1e^t}{1 + c_1e^t}$

a. If any solution passes through the point (0, 6), then there is $c_1$ such that the point (0, 6) satisfies the solution $P = \frac{c_1e^t}{1 + c_1e^t}$

Substitute $t = 0, P = 6$ in $P = \frac{c_1e^t}{1 + c_1e^t}$ and then solve the equation to obtain $c_1$

$P(t) = \frac{c_1e^t}{1 + c_1e^t}\\P(0) = \frac{c_1e^0}{1+c_1e^0}\\ 6 = \frac{c_1}{1 + c_1}\\ c_1 = -\frac{6}{5}$

Therefore, the curve $P(t) = -\frac{6e^t}{5 - 6e^t}$ passes through the point (0, 6)

b. If any solution passes through the point(0, 1), then there is $c_1$ such that the point (0, 1) satisfies the solution $P = \frac{c_1e^t}{1+c_1e^t}$

$P(t) = \frac{c_1e^t}{1 + c_1e^t}\\ P(0) = \frac{c_1e^0}{1 + c_1e^0}\\ 1 = \frac{c_1}{1+c_1} \\1 + c_1 = c_1$

this is not possible

Hence, there is no curve $P(t)$ that exists which passes through the point (0, 1)

4 0

3 years ago