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vichka [17]
3 years ago
12

Help find x out of these 4 questions i can’t find the answer anywheew

Mathematics
1 answer:
babunello [35]3 years ago
4 0

Answer:

Option D. 11√6/2

Step-by-step explanation:

We'll begin by calculating the side opposite to angle 60°.

This is illustrated below:

Angle θ = 60°

Opposite =?

Hypothenus = 11

Using the sine ratio, we can obtain the side opposite to angle 60° as follow:

Sine θ = Opposite/Hypothenus

Sine 60 = Opposite /11

Cross multiply

Opposite = 11 × Sine 60

Sine 60 = √3/2

Opposite = 11 × √3/2

Opposite = 11√3/2

Finally, we shall determine the value of x as follow:

Angle θ = 45°

Opposite = 11√3/2

Hypothenus = x

Using the sine ratio, we can obtain the value of x as shown below:

Sine θ = Opposite/Hypothenus

Sine 45° = 11√3/2 /x

Cross multiply

x × Sine 45° = 11√3/2

Sine 45° = 1/√2

x × 1/√2 = 11√3/2

x/√2 = 11√3/2

Multiply through by √2

x = √2 × 11√3/2

x = 11√6/2

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<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

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To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

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