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NemiM [27]
3 years ago
14

each face of cabinet 413S is in the shape of a rectangle. What is the volume of Model 413S in cubic feet? Dimension are 24 by 72

by 18. ( in inches )
Mathematics
1 answer:
lbvjy [14]3 years ago
7 0
To calculate a volume of a rectangle prism, a cabinet we only need to multiply the dimensions it has, those are height, width, deep:
v = (24)(72)(18)
v = 31104 in^3
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Please help me out!!
solniwko [45]
The slope is 1 because it is parallel and y=x+b, so, 2=-3+b and b=5
y=x+5

8 0
3 years ago
Find the perimeter of the polygon round your answer to the nearest tenth.
Volgvan
The correct answer is 39 units.Parameter is the
sum of the lengths of all sides of a polygon.
The sides of the polygon are PT, TS, SR, RQ,
and QP.
3 0
2 years ago
For about $1 billion in new space shuttle expenditures, NASA has proposed to install new heat pumps, power heads, heat exchanger
11111nata11111 [884]

Answer:

The probability of one or more catastrophes in:

(1) Two mission is 0.0166.

(2) Five mission is 0.0410.

(3) Ten mission is 0.0803.

(4) Fifty mission is 0.3419.

Step-by-step explanation:

Let <em>X</em> = number of catastrophes in the missions.

The probability of a catastrophe in a mission is, P (X) = p=\frac{1}{120}.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X </em>is:

P(X=x)={n\choose x}\frac{1}{120}^{x}(1-\frac{1}{120})^{n-x};\x=0,1,2,3...

In this case we need to compute the probability of 1 or more than 1 catastrophes in <em>n</em> missions.

Then the value of P (X ≥ 1) is:

P (X ≥ 1) = 1 - P (X < 1)

             = 1 - P (X = 0)

             =1-{n\choose 0}\frac{1}{120}^{0}(1-\frac{1}{120})^{n-0}\\=1-(1\times1\times(1-\frac{1}{120})^{n-0})\\=1-(1-\frac{1}{120})^{n-0}

(1)

Compute the compute the probability of 1 or more than 1 catastrophes in 2 missions as follows:

P(X\geq 1)=1-(1-\frac{1}{120})^{2-0}=1-0.9834=0.0166

(2)

Compute the compute the probability of 1 or more than 1 catastrophes in 5 missions as follows:

P(X\geq 1)=1-(1-\frac{1}{120})^{5-0}=1-0.9590=0.0410

(3)

Compute the compute the probability of 1 or more than 1 catastrophes in 10 missions as follows:

P(X\geq 1)=1-(1-\frac{1}{120})^{10-0}=1-0.9197=0.0803

(4)

Compute the compute the probability of 1 or more than 1 catastrophes in 50 missions as follows:

P(X\geq 1)=1-(1-\frac{1}{120})^{50-0}=1-0.6581=0.3419

6 0
3 years ago
Anyone answer please it is my H.W <br>don't spam ❌❌​
Nata [24]

Answer:

2a) = soln

20/3

2) divide the numeral by dinominator..

3)a) soln 7 3/4

4*7+3

= 31

do all like this ❣️

3 0
2 years ago
Read 2 more answers
In the triangle shown below what is the approximate value of x
kumpel [21]

it's a right triangle so you use Pythagoras' theorem.

√28²-14²=

√784 - 196 =

√588

24.24 units (rounded 24.25)

your answer is 24.25 units

5 0
3 years ago
Read 2 more answers
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