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3 years ago

What is median of this histogram

Mathematics

1 answer:

Molodets [167]3 years ago

3 0

Answer: You take the 2 middle columns in this case the purple gray looking one and the brown one and add them together divide them by 2

Step-by-step explanation:

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Is it even an option on my Penn Foster Exam?

Anton [14]

Lel nope gotta take it

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3 years ago

Obtén lo que se te pide, dadas las dos matrices siguientes.

Ivan

I think its b because it makes sense

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3 years ago

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Flauer [41]

Answer:Can somebody please help

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What is the coefficient of x2y3 in the expansion of (2x + y)5?

Zigmanuir [339]

Option C:

The coefficient of $x^{2} y^{3}$ is 40.

Solution:

Given expression:

$(2 x+y)^{5}$

Using binomial theorem:

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here $a=2 x, b=y$

Substitute in the binomial formula, we get

$(2x+y)^5=\sum_{i=0}^{5}\left(\begin{array}{l}5 \\i\end{array}\right)(2 x)^{(5-i)} y^{i}$

Now to expand the summation, substitute i = 0, 1, 2, 3, 4 and 5.

$$=\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}+\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1}+\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}+\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}$

$$+\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}+\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}$

Let us solve the term one by one.

$$\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}=32 x^{5}$

$$\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1} = 80 x^{4} y$

$$\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}= 80 x^{3} y^{2}$

$$\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}= 40 x^{2} y^{3}$

$$\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}= 10 x y^{4}$

$$\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}=y^{5}$

Substitute these into the above expansion.

$(2x+y)^5=32 x^{5}+80 x^{4} y+80 x^{3} y^{2}+40 x^{2} y^{3}+10 x y^{4}+y^{5}$

The coefficient of $x^{2} y^{3}$ is 40.

Option C is the correct answer.

5 0

2 years ago

Help me out please !!!!

Brums [2.3K]

Answer:

0.06 liters

Step-by-step explanation:

acid concentration of 65% means that it of 100 units of that solution 65 are acid, and the remaining 35 are water.

so, 100 units are 0.2 liters in this example.

that means that 65/100 × 0.2 = 0.13 liters are acid.

35/100 × 0.2 = 0.07 liters are water

we get a 50% concentration, when we have the same amount of water and acid in the solution (acid is only half of 50% of the solution).

the account of acid remains the same, as we are only adding water.

so, how much water do we need to get from 0.07 liters to 0.13 liters (the same as the already present acid) ?

0.13 - 0.07 = 0.06 liters

4 0

3 years ago