Question

Each step in the process below has 80% yield.

Answer 1

Answer:

8.96 mol of HCl is produced.

Explanation:

CH₄ + 4Cl₂ → CCl₄ + 4HCl   80% yield

CCl₄ + 2HF → CCl₂F₂ + 2HCl   80% yield

The first reaction:

1 mol CH₄ ____ 4 mol HCl                  1 mol CH₄ ____ 1 mol CCl₄

2 mol CH₄ ____       x                          2 mol CH₄ ____       x

x = 8 mol HCl                                        x = 2 mol HCl

The first reaction would lead to 8 mol of HCl, but as its yield is 80%, the total ammount of HCl produced is 0.8x8 = 6.4 mol HCl

The same applies for CCl₄: 0.8x2 = 1.6 mol CCl₄

The second reaction:

1 mol CCl₄ ____ 2 mol HCl                  

1.6 mol CH₄ ____       x                          

x = 3.2 mol HCl                                    

The second reaction would lead to 3.2 mol of HCl, but as its yield is 80%, the total ammount of HCl produced is 0.8x3.2 = 2.56 mol HCl  

Therefore, considering both reactions, 8.96 mol of HCl is produced.