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Diano4ka-milaya [45]
3 years ago
11

Which of the following on the periodic table corresponds to a principal energy level?

Chemistry
2 answers:
kolbaska11 [484]3 years ago
5 0

Answer:

representative elements

r-ruslan [8.4K]3 years ago
3 0

Answer: transition element

Explanation:

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How many moles of oxygen gas can 0.882 mol of hydrogen peroxide produce if decomposition is complete? 2H2O2 (l) → 2H2O(l) + O2(g
andreyandreev [35.5K]
We are given the chemical reaction and the amount of reactant used for the process. We use these data together to obtain what is asked. We do as as follows:

0.882 mol H2O2 ( 1 mol O2 / 2 mol H2O2 ) = 0.441 mol O2 produced

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Explanation:

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2 years ago
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What is the net ionic equation for the reaction of alum (KAl(SO4)2.12H2O.) and KOH?
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7 0
3 years ago
A solution is made using 148.5 g of dimethyl ether (MM = 46.07 g/mol) and 90.0 g of methanol (MM = 32.04 g/mol). What is the mol
Mariulka [41]

Answer:

0.534

Explanation:

Mole fraction can be calculated using the formula:

Mole fraction = number of moles of solute ÷ number of moles of solvent and solute (solution).

In this question, solute is dimethyl ether while the solvent is methanol.

Mole (n) = mass (M) ÷ molar mass (MM)

Mole of solute (dimethyl ether) = 148.5 ÷ 46.07

= 3.22moles.

Mole of solvent (methanol) = 90 ÷ 32.04

= 2.81moles.

Total moles of solute and solvent = 3.22 + 2.81 = 6.03moles.

Mole fraction of dimethyl ether = number of moles of dimethyl ether ÷ number of moles of solution (dimethyl ether + methanol)

Mole fraction = 3.22/6.03

= 0.534

6 0
3 years ago
Determine the concentration of a solution prepared by diluting 20.0 mL of 2.00 M NaCl to 250.0 mL. Please show your work.
yawa3891 [41]

0.16 M is the concentration of a solution prepared by diluting 20.0 ml of 2.00 M NaCl to 250.0 ml.

Explanation:

Data given:

Initial volume of NaCl, V1 = 20 ml

initial molarity of the NaCl solution = 2M

Final volume of the NaCl solution = 250 ml

final molarity of the diluted solution = ?

from the information given, the formula for dilution used is:

Minitial Vinitial = Mfinal Vfinal

putting the values in the rearranged equation:

V final = \frac{Minitial Vinitial }{Vfinal}

V final = \frac{20 X 2}{250}

Mfinal = 0.16 M

Thus it can be seen that when a 20 ml solution having molarity of 2M is diluted to 250 ml the molarity decreases to 0.16 M.

6 0
3 years ago
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