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3 years ago

Which of the following on the periodic table corresponds to a principal energy level?

Chemistry

2 answers:

kolbaska11 [484]3 years ago

5 0

Answer:

representative elements

r-ruslan [8.4K]3 years ago

3 0

Answer: transition element

Explanation:

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A covalent bond in which electrons are shared unequally is

tekilochka [14]

Covalent bonds = sharing of electrons between two atoms of the same elements or elements close to each other on the periodic table. Usually they are metals sometimes non-metals. In polar bonds electrons are shared unequally. Non polar bonds share electrons equally.

7 0

3 years ago

What does condensation mean in the water cycle?

tester [92]

Condensation is the process by which water vapor in the air is changed into liquid water. Condensation is crucial to the water cycle because it is responsible for the formation of clouds. ... Condensation is the opposite of evaporation.

4 0

3 years ago

Read 2 more answers

Water is poured into a conical container at the rate of 10 cm3/sec. The cone points directly down, and it has a height of 20 cm

8090 [49]

Answer:

\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{2}

Explanation:

Hello,

The suitable differential equation for this case is:

$\frac{dV}{dt}=10\frac{cm^3}{s}$

As we're looking for the change in height with respect to the time, we need a relationship to achieve such as:

$\frac{dh}{dt} = ?*\frac{dV}{dt}$

Of course, $?=\frac{dh}{dV}$ .

Now, since the volume of a cone is $V=\pi r^2h/3$ and the ratio $r/h=15/20=3/4$ or $r=3/4h$ , the volume becomes:

$V=\pi (\frac{3}{4} h)^2h/3= \frac{3}{16}\pi h^3$

We proceed to its differentiation:

$\frac{dV}{dh} =\frac{9}{16} \pi h^2\\\frac{dh}{dV} =\frac{16}{9 \pi h^2}$

Then, we compute $\frac{dh}{dt}$

$\frac{dh}{dt} = \frac{16}{9 \pi h^2}*\frac{dV}{dt}\\\frac{dh}{dt} = \frac{16}{9\pi h^2}*10\frac{cm^3}{s} =\frac{160}{9 \pi h^2}$

Finally, at h=2:

$\frac{dh}{dt}_{h=2cm} =\frac{160}{9\pi 2^2}\\\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{s}$

Best regards.

4 0

3 years ago

Which member of each pair is more soluble in diethyl ether? Why? (c) MgBr₂(s) or CH₃CH₂MgBr(s)

White raven [17]

CH3CH2MgBr is more soluble in diethyl ether .

We know that polar solvent dissolve in polar solvent very perfectly . as diethyl ether is a polar solvent so it have dipole -dipole interaction .

Hence the compound with similar interaction can dissolve in diethyl ether .

Here , MgBr2 is an ionic compound . there is ion-ion interactions occurs which is not similar to dipole -dipole interaction in diethyl ether .hence the solubility of MgBr2 in diethyl ether is less .

but in case of CH3CH2MgBr there are both polar and nonpolar end .CH3CH2 is the nonpolar end and MgBr is the polar end .

thus with the nonpolar end solute interact using depression forces and with polar end solute interact using dipole-dipole interaction . so CH3CH2MgBr is more soluble .

Learn more about polar solvent here :

brainly.com/question/3184550

#SPJ4

4 0

2 years ago

NISA [10]

Answer:

C. involve the attraction of opposite charges

Explanation:

Ionic bonding involves the attraction between oppositely charged ions, as in Na⁺ Cl⁻.

Covalent bonding involves the attraction between negatively charged electrons and positivey charged nuclei, as in a C-H bond.

A is wrong. Ionic bonding involves the transfer of electrons.

B is wrong. Covalent bonding involves the sharing of electrons.

D is wrong. Ionic bonds are usually stronger than covalent bonds.

5 0

3 years ago