We are given the chemical reaction and the amount of reactant used for the process. We use these data together to obtain what is asked. We do as as follows:
0.882 mol H2O2 ( 1 mol O2 / 2 mol H2O2 ) = 0.441 mol O2 produced
Hope this answers the question.
Answer: See attached image
Explanation:
<span>The net ionic equation for the reaction of alum (KAl(SO4)2.12H2O.) and KOH is </span>the solid AlOH3 formed.
Answer:
0.534
Explanation:
Mole fraction can be calculated using the formula:
Mole fraction = number of moles of solute ÷ number of moles of solvent and solute (solution).
In this question, solute is dimethyl ether while the solvent is methanol.
Mole (n) = mass (M) ÷ molar mass (MM)
Mole of solute (dimethyl ether) = 148.5 ÷ 46.07
= 3.22moles.
Mole of solvent (methanol) = 90 ÷ 32.04
= 2.81moles.
Total moles of solute and solvent = 3.22 + 2.81 = 6.03moles.
Mole fraction of dimethyl ether = number of moles of dimethyl ether ÷ number of moles of solution (dimethyl ether + methanol)
Mole fraction = 3.22/6.03
= 0.534
0.16 M is the concentration of a solution prepared by diluting 20.0 ml of 2.00 M NaCl to 250.0 ml.
Explanation:
Data given:
Initial volume of NaCl, V1 = 20 ml
initial molarity of the NaCl solution = 2M
Final volume of the NaCl solution = 250 ml
final molarity of the diluted solution = ?
from the information given, the formula for dilution used is:
Minitial Vinitial = Mfinal Vfinal
putting the values in the rearranged equation:
V final = 
V final = 
Mfinal = 0.16 M
Thus it can be seen that when a 20 ml solution having molarity of 2M is diluted to 250 ml the molarity decreases to 0.16 M.
