The X and Y components are as follows;
1. X = 35 * cos 57 = 19. 1m/s; Y = 35 * sin 57 = 29.4 m/s
2. X = 12 * -cos 34 = -10 m/s; Y = 12 * -sin 34 = -6.7 m/s
3. X = 8 * -cos 90 = 0 m/s; Y = 12 -sin 90 = -8 m/s
4. X = 20 * cos 75 = 5. 2m/s; Y = 20 * (-sin 75) = -19.3 m/s
<h3>What are the horizontal and vertical components of the vectors?</h3>
The horizontal and vertical components of the velocities are given as follows:
- Horizontal component, X = x cos θ
- Vertical component, Y = y sin θ
1. 35 m/s at 57° from x-axis
X = 35 * cos 57 = 19. 1m/s
Y = 35 * sin 57 = 29.4 m/s
2. 12m/s at 34° S of W
X = 12 * -cos 34 = -10 m/s
Y = 12 * -sin 34 = -6.7 m/s
3. 8 m/s at South
X = 8 * -cos 90 = 0 m/s
Y = 12 -sin 90 = -8 m/s
4. 20 m/s at 275° from x-axis
X = 20 * cos 75 = 5. 2m/s
Y = 20 * (-sin 75) = -19.3 m/s
In conclusion, the X and Y components are found by taking cosines and sine of the angles.
Learn more about horizontal and vertical components at: brainly.com/question/26446720
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Answer:
0.0354 kg/s
Explanation:
= Initial displacement = 0.5 m
= Final displacement = 0.1 m
m = Mass of egg = 55 g
t = Time taken = 5 seconds
Displacement of the oscillator under damping motion is given by
![x=Ae^{-\frac{b}{2m}t}cos(\omega't+\phi)](https://tex.z-dn.net/?f=x%3DAe%5E%7B-%5Cfrac%7Bb%7D%7B2m%7Dt%7Dcos%28%5Comega%27t%2B%5Cphi%29)
For maximum displacement
![cos(\omega't+\phi)=1](https://tex.z-dn.net/?f=cos%28%5Comega%27t%2B%5Cphi%29%3D1)
![A_2=A_1e^{-\frac{b}{2m}t}](https://tex.z-dn.net/?f=A_2%3DA_1e%5E%7B-%5Cfrac%7Bb%7D%7B2m%7Dt%7D)
From this equation we get
![b=\frac{2m}{t}ln\frac{A_1}{A_2}\\\Rightarrow b=\frac{2\times 0.055}{5}ln\frac{0.5}{0.1}\\\Rightarrow b=0.0354\ kg/s](https://tex.z-dn.net/?f=b%3D%5Cfrac%7B2m%7D%7Bt%7Dln%5Cfrac%7BA_1%7D%7BA_2%7D%5C%5C%5CRightarrow%20b%3D%5Cfrac%7B2%5Ctimes%200.055%7D%7B5%7Dln%5Cfrac%7B0.5%7D%7B0.1%7D%5C%5C%5CRightarrow%20b%3D0.0354%5C%20kg%2Fs)
The magnitude of the damping constant is 0.0354 kg/s
Answer:
An electron has a negative electric charge.
Answer:
Explanation:
Let Torque due to friction be
F
Net torque
= 46 - F
Angular impulse = change in angular momentum
=( 46 - F ) x 17 = I X 580
When external torque is removed , only friction creates torque reducing its speed to zero in 120 s so
Angular impulse = change in angular momentum
F x 120 = I X 580
( 46 - F ) x 17 = F x 120
137 F = 46 x 17
F = 5.7 Nm
b )
Putting this value in first equation
5.7 x 120 = I x 580
I = 1.18 kg m²
Answer:
Explanation:
River is 7.5 m wide . Time taken by it cover this displacement
= displacement / velocity
= 7.5 / 0.4
= 18.75 s
During this period , swimmer will have a displacement of 30 m due to velocity of river water .
Displacement of 30 m downstream will be due to flow of river .
velocity of water flow = displacement / time
= 30 / 18.75
= 1.6 m /s