Answer: push force gravity tension and reverse force
Explanation: sense they are pushing the box there is a push force gravity because this is likely on earth tension because it is the reverse of gravity and the reverse force because you have to have the reverse of push
Answer:
F = ma The force of friction for a 7.5-kg object being pushed horizontally at a constant A 30-kg wooden box is resting on a carpeted surface. If the ... An applied force of 21 N accelerates a 9.0-kg wagon at 2.0 m/s² along the sidewalk. (u=0,034. 5. A sled of mass of 50.0 kg is pulled along a flat, snow-covered ground.
Explanation:
Answer:
Explanation:
The path of waves reaching directly and through reflection from ionosphere will form a isosceles triangle.
Let the height be h . This will be height of a triangle of equal side whose base is of length 32 km. we shall calculate the length of one side of this triangle .
this length be l
l² = 16² + h²
l = √(256 +h² )
2l = 2√(256 +h² )
path difference = 2l - 32 km
For destructive interference
path difference = wavelength /2 for minimum height .
2l - 32 = .344/2
2√(256 +h² )- 32 = . 172
2√(256 +h² ) = 32.172
4(256 +h² ) = 1035
(256 +h² ) = 258.76
h² = 2.76
h = 1.66 km
We are given an object sliding down an incline with a friction force. A free-body diagram of the system is the following:
Now we will add the forces in the x-direction:
We will consider the forces that are in the direction of the movement as positive and the ones in the direction against the movement as negative. Plugging in the forces:
Now we solve for the friction force:
Multiplying both sides by -1:
Now we determine the x-component of the weight using the following triangle:
From the triangle we can use the function cosine as follows:
From this we can solve for the x-component of the weight by multiplying both sides by "mg":
Now we use this expression and replace it in the sum of forces:
Now we plug in the known values:
Solving the operations:
Therefore, the friction force is 171.5 Newtons.
The answer to the first question is -1.5 m/s^2