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kolbaska11 [484]
3 years ago
15

A student reaches into a bag of objects.which property of the objects can be observed by using the sense of touch

Physics
2 answers:
matrenka [14]3 years ago
8 0
Id shoot for texture
enot [183]3 years ago
6 0
They can tell the shape of the object by using the sense of touch
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Something that is not magnetic
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Describe a structural adaption that a snake has. What challenge does it overcome? PLZ HELP ASAP
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A vertically polarized light wave of intensity 1000 mW/m2 is coming toward you, out of the screen. After passing through this po
Bingel [31]

Answer:

The intensity is I  =  500 mW/m^2

Explanation:

From the question we are told that

    The  intensity of the unpolarized light is I_o  =  1000 \ m W  /m^2  =  1000 *10^{-3} \ W/m^2

Generally the intensity of the light emerging from the polarizer is  mathematically represented as

          I  =  \frac{I_o}{2}

substituting values

         I  =  \frac{1000 *10^{-3}}{2}

         I  = 500 *10^{-3} W/m^2

         I  =  500 mW/m^2

3 0
3 years ago
5. A ball rolls off a 1.5 m tall horizontal table and lands on the floor 0.70 m away.
pav-90 [236]

Take the starting position of the ball 1.5 m above the floor to be the origin. Then at time t, the ball's horizontal and vertical positions from the origin are

x = v₀ t

y = -1/2 gt²

where v₀ is the initial speed with which it rolls off the edge and g = 9.8 m/s².

A. The floor is 1.5 m below the origin, so we solve for t when y = -1.5 m :

-1.5 m = -1/2 gt²

⇒   t² = (3.0 m)/g

⇒   t = √((3.0 m)/g) ≈ 0.55 s

B. It would take the same amount of time.

C. The ball travels a horizontal distance of 0.70 m before reaching the floor, so we solve for v₀ with t = 0.55 s :

0.70 m = v₀ (0.55 s)

⇒   v₀ = (0.70 m) / (0.55 s) ≈ 1.3 m/s

D. At time t, the ball has horizontal and vertical velocity components

v[x] = 1.3 m/s

v[y] = -gt

so the horizontal component of the ball's final velocity vector is the same as the initial one, 1.3 m/s.

E. The vertical component of velocity would be

v[y] = -g (0.55 s) ≈ -5.4 m/s

F. The magnitude of the final velocity would be

√((1.3 m/s)² + (-5.4 m/s)²) ≈ 5.6 m/s

G. The final velocity vector makes an angle θ with the horizontal such that

tan(θ) = (-5.4 m/s) / (1.3 m/s)

⇒   θ = arctan(-5.4/1.3) ≈ -77°

i.e. approximately 77° below the horizontal.

3 0
2 years ago
A sample of radium-226 will decay to 1/4 of its original amount after 3200 years. What is the half-life of radium-226?
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