Answer:
The block has an acceleration of 
Explanation:
By means of Newton's second law it can be determine the acceleration of the block.
(1)
Where
represents the net force, m is the mass and a is the acceleration.
(2)
The forces present in x are
and
(the friction force):

Notice that
subtracts to
since it is at the opposite direction.

The forces present in y balance each other:

Therefore:
(3)
But
and writing (3) in terms of a it is get:

So the block has an acceleration of
.
research the different time zone around the world, and characteristics of each
I think it’s 15cm
Might be 7cm
We can use the kinematic equation

where Vf is what we are looking for
Vi is 0 since we start from rest
a is acceleration
and d is the distance
we get
(Vf)^2 = (0)^2 + 2*(2)*(500)
(Vf)^2 = 2000
Vf = about 44.721
or 44.7 m/s [if you are rounding this by significant figures]
First one is D and Second one is B