C) Daca AD = 5cm AB = 15cm AC = 18cm si BC = 12cm, calculati AE, DE, DB, si EC?

What is the difference, in meters, between the length of the longest line and the length of the shortest line?

ivolga24 [154]

Answer:

$Range = 3.169m$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the difference between the shortest and the longest

This question implies that we calculate the range.

$Range = Longest - Shortest$

From the table, we have:

$Longest = 8.7m$

$Shortest = 5.531m$

So, we have:

$Range = 8.7m- 5.531m$

$Range = 3.169m$

5 0

3 years ago

Use distributive property to factor method 1. Use distributive property to expand method 2.

sasho [114]

Step-by-step explanation:

I guess method 1 means to deal with whole factors.

x + 5 = (x - 2)(x + 5)

for (x + 5) <> 0 we can divide both sides by this factor :

1 = x - 2

x = 3

for the second solution we deal with

x + 5 = 0

x = -5

so, for x = -5 and x = 3 both functions deliver the same output, and these are the intersection points.

method 2 : we multiply the expression out and solve it then

x + 5 = (x - 2)(x + 5)

x + 5 = x² + 5x - 2x - 10 = x² + 3x - 10

0 = x² + 2x - 15

the general solution to such a square equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 1

b = 2

c = -15

x = (-2 ± sqrt(2² - 4×1×-15))/(2×1) =

= (-2 ± sqrt(4 + 60))/2 = (-2 ± sqrt(64))/2 = (-2 ± 8)/2 =

= -1 ± 4

x1 = -1 + 4 = 3

x2 = -1 - 4 = -5

and you get the 2 solutions again. as expected, they are the same as with method 1, of course.

4 0

2 years ago

Jane paid $40 for an item after she received a 20% discount. Jane's friend says this means that the original price of the item w

yanalaym [24]

Answer:

Yes,

Step-by-step explanation:

$40+20%=$48 . Probably Jane's friend is correct

6 0

3 years ago

Posted this question 1000times. Plz some answer plz plz i beg. Plz show all working, thank you sir

Novosadov [1.4K]

Answer:

$\approx 26.16\:\mathrm{m}$

Step-by-step explanation:

Let $h$ be the height of the tree. In reference to the tree and bird, a right triangle is formed. We can write the following trig function for that right triangle:

$\tan28^{\circ}=\frac{h}{15},\\h=15\tan28^{\circ},\\h\approx 7.98\:\mathrm{m}$ .

Now we can use this to find the hypotenuse of this triangle (the distance between the cat and the bird):

Let the distance between the cat and bird be $k$ . Then,

$7.98^2+15^2=k^2,\\k\approx 16.99\:\mathrm{m}$ . This is one side of the triangle that is formed by the cat, bird, and mouse.

The right triangle formed by the tree, cat, and mouse shares the height $h$ with the other right triangle, as we found earlier. Let $l$ represent the hypotenuse of this triangle or the distance between the cat and mouse. We then have the following trig function:

$\sin 40^{\circ}=\frac{7.98}{l},\\l=\frac{7.98}{\sin40^{\circ}}\approx 12.41\:\mathrm{m}$ . This is another side of the triangle that is formed by the cat, bird, and mouse.

The triangle that is formed by the cat, bird, and mouse has shares an angle of $125^{\circ}$ with the base of the auxiliary pyramid. The other angles, however, are not shared.

Since we have two sides and the angle between these two sides, we can use the Law of Cosines to find the other side (the distance between the mouse and bird). The Law of Cosines is given by:

$m^2=k^2+l^2-2kl\cos M$ , where $m$ is the distance between the bird and the mouse and the other variables are defined above.