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3 years ago

Find the median.

Mathematics

2 answers:

labwork [276]3 years ago

8 0

<h3>Hello there!</h3>

Your answer asks to find the median of the given numbers.

<h3>Answer: B). 9</h3>

To find the median, you would need to sort of the numbers from least to greaters.

The given numbers we have:

12, 8, 5, 6, 1, 10, 13, 11

Now, just sort them from least to greatest.

1, 5, 6, 8, 10, 11, 12 ,13

What you would do next is eliminate the numbers on the side, one by one, in order to get your median.

$1, 5, 6, 8, 10, 11, 12 ,13\\\\5, 6, 8, 10, 11, 12\\\\6, 8, 10, 11\\\\8, 10$

We ended up with two numbers, 8 and 10. Since we didn't end up with one number, we're going to have to add those numbers, and then divide it by two.

$8+10=18\\\\18\div2=9$

You should get 9.

Therefore, the median would be 9.

B). 9 should be your FINAL answer

<h3>I hope this helps!</h3><h3>Best regards, MasterInvestor</h3>

Kruka [31]3 years ago

8 0

Answer:

The correct answer is option B. 9

Step-by-step explanation:

Median:

Median of a data set means that, the central data when arrange all the in ascending or descending order

It is given a data set ,

12, 8, 5, 6, 1, 10, 13, 11

<u>To find the median of data set</u>

Here there are 8 items, median is average of 4th and 5th terms

Ascending order,

1, 5, 6, 8, 10, 11, 12, 13

Median = (8 + 10)/2 = 18/2 = 9

The correct answer is option B. 9

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Answer:

{7, 11, 15, 19}

Step-by-step explanation:

The function is defined by the formula y = 2x + 1 ........ (1)

Now, domain of the function are given to be {3, 5, 7, 9}

Hence, from equation (1), at x= 3, y = 2 × 3 + 1 = 7

Now, at x = 5, y = 2 × 5 + 1 = 11

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Finally, at x = 9, y = 2 × 9 + 1 = 19

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Answer:

$T_7 = 11$

$T_n = 2n- 3$

Step-by-step explanation:

Given

$S_n = n^2 -2n$

$T_n = S_n - S_{n-1}$

Solving (a): T7

Substitute 7 for n in $T_n = S_n - S_{n-1}$

$T_7 = S_7 - S_{7-1}$

$T_7 = S_7 - S_6$

Calculate S7 and S6

$S_n = n^2 -2n$

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$S_6 = 6^2 - 2 * 6 = 24$

So:

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Solving (b): Tn

$T_n = S_n - S_{n-1}$

Where $S_n = n^2 -2n$

Calculate $S_{n-1}$

We have:

$S_{n-1} =(n-1)^2 - 2(n-1)$

Open brackets

$S_{n-1} = n^2 -2n + 1 -2n +2$

$S_{n-1} = n^2 -2n-2n + 1 +2$

$S_{n-1} = n^2 -4n + 3$

So:

$T_n = S_n - S_{n-1}$

$T_n = n^2 - 2n - (n^2 -4n + 3)$

$T_n = n^2 - 2n - n^2 +4n - 3$

Collect Like Terms

$T_n = n^2 - n^2- 2n +4n - 3$

$T_n = 2n- 3$

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