Answer:
where the parameter s is a real number and u=P1-P0 is a line direction vector. Using this representation P(0)=P0, P(1)=P1, and when s.ge-0.le-1, P(s) is a point on the finite segment P0P1 where s is the fraction of P(s)'s distance along the segment. That is, s = d(P0,P(s)) / d(P0,P1). Further, if s < 0 then P(s) is outside the segment on the P0 side, and if s > 1 then P(s) is outside the segment on the P1 side.
Step-by-step explanation:
Answer:
3x - 6x - 7 = 29 <u>Given</u>
<u>-----------------------------------</u>
3x - 6x -7 = 29
+ 7 + 7 <u>Addition property of equality</u>
3x - 6x = 36
<u>--------------------------------------------------------------</u>
3x - 6x = 36
<u>(</u>3x + -6x) = 36 <u>Combine like terms</u>
-3x = 36
<u>--------------------------------------------------------------</u>
-3x = 36
(-3x = 36)/ -3 <u>Division property of equality</u>
x = -12
<u />
Step-by-step explanation:
I tried to seperate the steps so you can go through them. First you had to add on both sides to take out the like terms, then combine the 3x and the -6x to make -3x (easier to look at and divide), and finally divide to find X. the end product using X cannot be a negative because its a filler space for a real number.
Hope this helps :)
Given expression : 
.
We need to apply power property of logs to rewrite it.
According to log rule of exponents:
If we compare given expression with the rule the exponent part is f, base is 6.
Therefore, we need to bring exponent f in front of log.
Therefore, 
.
<h3>And correct option is second option
</h3>
Answer:
Step-by-step explanation:
11) strategy: since they tell us. indirectly, that the length of JK is the same as LM then we can set those two equal, solve for X and then.. when we have X we can figure out the lenght of JK and LM and then just divide that by 2 go get PK ( :0 Player Killer ??? no , not that PK)
solve JK and LM
3x + 23 =9x-19
42 = 6x
7 = x
now that we know x = 7 plug it into either equation to come up with the length of JK or LM . I'll pick JK just b/c it was 1st
3(7) + 23 = JK
21+23 = JK
44 = JK
now take half of 1/2*JK= 22 that is PK ( are you sure that 's not player killer?)
PK = 22
12) strategy: set the two arcs BG and GC equal and solve for X, then plug x into either equation and the multiply the answer by 2 to find arc AB
9x-20 = 5x + 28
4x = 48
X = 12
9(12) -20 = BG
88 = BG
2*88 + AB
176 = AB
13) done
14) strategy: find the angle at L, and that will also be the arc of MK
<em>copy and past the below</em> helpful trig functions into your computer
Use SOH CAH TOA to recall how the trig functions fit on a triangle
SOH: Sin(Ф)= Opp / Hyp
CAH: Cos(Ф)= Adj / Hyp
TOA: Tan(Ф) = Opp / Adj
<em>copy and past the above</em> :
use which ever trig function you want , we have all the sides of the triangle, I'll use CAH
Cos(Ф) = 9/15
Ф = arcCos(9/15)
Ф = 53.13010°
arc MK = 53.13010°
15) strategy: arc JK is just 2 times MK
2*MK = 106.26020°
arc MK = 106.26020°
16) find arc JPK strategy: JPK is just the remaining part of a full circle of 360 - MK = 253.7397°
arc JPK = 253.7397°
