Answer:
its A i just took the test
In order for the triangle to be called an isosceles right triangle, it must satisfy both conditions: XZ and XY must be perpendicular to each other, and XZ = XY.
To determine whether two lines are perpendicular, their slopes must be negative reciprocals of each other.
Solving for the slopes of XZ and XY:
slope of XZ = (y₂-y₁) / (x₂-x₁) = (6-3)/(5-1) = 3/4
slope of XY = (y₂-y₁) / (x₂-x₁) = (3--1)/(1-4) = -4/3
-4/3 is the negative reciprocal of 3/4, therefore XZ and XY are perpendicular to each other.
Solving for distance:
XZ = √[(y₂-y₁)²+(x₂-x₁)²] = √[(6-3)²+(5-1)²] = 5
XY = √[(y₂-y₁)²+(x₂-x₁)²] = √[(3--1)²+(1-4)²] = 5
<span>The slope of XZ is 3/4, the slope of XY is -4/3, and XZ = XY = 5. </span>
F(9)=-(9)2-20
= -38
I hope it helps!
Domain is the x value. So you would just plug in every value in the domain set into the f(x) function.
5 (-2) + 4 =
-6
5 (3) + 4 =
19
5 (5) + 4 =
29
Your answer is B.
Answer:
80
Step-by-step explanation:
x³ + x²
4³ + 4²
64 + 16
80