The last one is correct because the line is not going up or down it’s every where so it’s the last one
Answer:
(x +3)^2 + (y -3)^2 = 3^2
Step-by-step explanation:
Your first task is to find the center.
The longest possible line of the circle goes from (-3,0) to (-3,6)
So the center is at the midpoint of these two points.
The midpoint is at (-3 - 3)/2 , (6+ 0)/2 or (-3,3)
That gives you the center of the circle.
So far what you have is
(x +3)^2 + (y -3)^2 = r^2
Now the distance of the center to the bottom point is (-3,3) to (-3,0)
r^2 = (x2 - x1)^2 + (y2 - y1)^2
x2 = - 3
x1 = - 3
y2 = 3
y1 = 0
r^2 = (-3 - -3)^2 + (3 - 0)^2
r^2 = 3^2
The entire answer is
(x +3)^2 + (y -3)^2 = 3^2
Answer:
The general admission ticket number is 160 and the upper box ticket number is 136
Step-by-step explanation:
In this case we can solve it using a 2x2 system of equations, like this:
let x be general admission tickets number
let y be upper box tickets number
So:
6.5 * x + 10 * y = 2400
x + y = 296 => x = 296 - y
Replacing, we are left with that:
6.5 * (296 - y) + 10 * y = 2400
1924 - 6.5 * y + 10 * y = 2400
10 * y - 6.5 * y = 2400 - 1924
3.5 * y = 476
y = 476 / 3.5
y = 136
Now to calculate x:
x = 296 - 136
x = 160
The general admission ticket number is 160 and the upper box ticket number is 136
Firstly, expand the equation.
Next, move the variable x to the left and all the constant to the right.
Then, solve for x.
