Answer: density =3.377g/cm³
Explanation:
Density =( molecular weight × effective number of atoms per unit cell) / (volume of unit cell × avogadro constant)
D= (M ×n) /(V×A)
M= 137g/mol
n= 2 (For BCC)
V=a³ , where a= 4r/√3
a= (4×222)/√3
a=512.69pm
a= 512.69×10^-10cm
V= ( 512.69×10^-10)^3
V= 1.3476×10^-22cm³
D= (137×2)/(1.3476×10^-22 × 6.02^23)
D= 3.377g/cm³
Therefore the density of barium is 3.377g/cm³
Answer:
Ans A
Explanation:
no. of shells determine the group
a.
A substance's specific heat tells you how much heat is required to increase the temperature of 1 g of that substance by 1°C.
The equation that establishes a relationshop between heat and change in temperature is
q = m • c • ∆T, where
q - heat absorbed
c - the specific heat of the substance, in your case of water
ΔT - the change in temperature, defined as the difference between the final temperature and the initial temperature
so:
q = 1.00 g • 4.18 J/g×°C • (75.0 - 38.5)°C
q = 152,57 J
just apply this formula for all exercises
Answer:
The answer to your question is Volume = 600 ml
Explanation:
Data
Volume 1 = 810 ml
Temperature 1 = 270°K
Pressure 1 = 1 atm
Volume 2 = ?
Pressure = 2 atm
Temperature 2 = 400°K
Process
1.- To solve this problem, use the Combine gas law.
P1V1 / T1 = P2V2 / T2
- Solve for V2
V2 = P1V1T2 / T1P2
2.- Substitution
V2 = (1)(810)(400) / (270)(2)
3.- Simplification
V2 = 324000 / 540
4.- Result
V2 = 600 ml
