Answer:
Explanation:
I basically looked up a solubility chart, but essentially when Al(aq) reacts with 
(aq), a solid is produced, meaning there is an insoluble substance that is produced.
Answer:
1.977 g/L
Nitrous oxide
Names
Molar mass 44.013 g/mol
Appearance colourless gas
Density 1.977 g/L (gas)
Melting point −90.86 °C (−131.55 °F; 182.29 K)
Friedrich Wohler was working with Ammonium Cyanate and found crystals of urea in his beakers
<em>A cylinder of argon gas contains 50.0 L of Ar at 18.4 atm and 127 °C. How many moles of argon are in the cylinder?</em>
<em />
Number moles of Argon : 28.03
<h3>Further explanation</h3>
Given
The volume of gas=50 L
P = 18.4 atm
T = 127+273=400 K
Required
moles of Argon
Solution
Use ideal gas Law :
Answer:
270 Joules
Explanation:
The specific heat capacity equation will be used for this question i.e.
Q = m. c. ΔT
Where; Q = Amount of heat
m = mass of substance
C = specific heat capacity of
substance
ΔT = change in temperature
(Final temp - initial temp)
However, for this unknown metal, we need to find the specific heat first by saying; C = Q / mΔT
Q= 135J, C=?, m= 10g, ΔT = (40-25 = 15°C)
C = 135 / 15 × 10
C = 135/150
C = 0.9 J/g°C
If the specific heat capacity of the unknown metal is 0.9 J/g°C, then at a mass of 20.0g, and a ΔT of 15°C, the amount of heat needed is:
Q = m. c. ΔT
Q = 20 × 0.9 × (40-25)
Q = 18 × 15
Q = 270J
270 Joules of heat is needed to increase the temperature of 20g of the metal from 25 - 40°C
