you add the masses of the reactants, because of conservation of mass. if there are two or more products they will ask you to find the mass of only one product or the sum of the mass of all products
Answer:
38.4 mol LiOH
Explanation:
Step 1: Write the balanced neutralization equation
2 LiOH + CO₂ ⇒ Li₂CO₃ + H₂O
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of LiOH to CO₂ is 2:1.
Step 3: Calculate how many moles of lithium hydroxide are required to react with 19.2 mol CO₂
19.2 mol CO₂ × 2 mol LiOH / 1 mol CO₂ = 38.4 mol LiOH
