Answer:
81.85%
Step-by-step explanation:
Given :
The average summer temperature in Anchorage is 69°F.
The daily temperature is normally distributed with a standard deviation of 7°F .
To Find:What percentage of the time would the temperature be between 55°F and 76°F?
Solution:
Mean = 
Standard deviation = 
Formula : 
Now At x = 55


At x = 76


Now to find P(55<z<76)
P(2<z<-1)=P(z<2)-P(z>-1)
Using z table :
P(2<z<-1)=P(z<2)-P(z>-1)=0.9772-0.1587=0.8185
Now percentage of the time would the temperature be between 55°F and 76°F = 
Hence If the daily temperature is normally distributed with a standard deviation of 7°F, 81.85% of the time would the temperature be between 55°F and 76°F.
Answer:
r=d/t
Step-by-step explanation:
d=rt
we are to make r the subject of the formula, so we remove t from the rhs.
we do this by dividing both sides by t
d divided by t= d/t and rt divided by t = r
therefore d/t =rt/t
= r=d/t
It will take JJ 4 hours to mow all of the yards in his block alone
Answer:

Step-by-step explanation:



Therefore, the coefficient of
is
.
The answer will be 40. As it doubles twice during 220mins- 10 to 20 and then 20 to 40.