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scZoUnD [109]
2 years ago
12

Dr. Burger rides his bike to work in the mornings. Usually, he leaves his house at 8:20 and gets to the office at 9:00 riding at

a rate of 15 miles an hour. On this particular morning he has overslept and leaves at 8:45. How fast does he need to ride to avoid being late
Mathematics
1 answer:
Vika [28.1K]2 years ago
8 0

Answer:

40 mph

Step-by-step explanation:

40 mins to bike usually, which means he bikes 10 miles. He needs to bike at a minimum of 10 miles in 15 mins, which translates to 40 miles in an hour.

P.S. He is going to surely be late.

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2z + 4y +8y - 32<br> How to solve
Sindrei [870]

Answer:

2z + 12y - 32

Step-by-step explanation:

1) 2z cannot be combined with any other number because no other number has the variable z.

2) 4y and 8y are both positive and van be combined. Therefore, it is 12y.

3) -32 cannot be combined with any other number because it doesn't have a variable that is the same as the others.

Therefore, the answer is 2z + 12y - 32

3 0
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If the circumference equals 40 pi inches, what is the radius?
Taya2010 [7]

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4 0
3 years ago
The formula to find the period of orbit of a satellite around a planet is T^2=(4pi^2/GM)r^3 where r is the orbit's mean radius,
Natalija [7]
The answer is r= \sqrt[3]{GMT^{2}/4 \pi^{2}}

T^{2} = \frac{4 \pi^{2}}{GM} r^{3}

Move \frac{4 \pi^{2} }{GM} to the other side of the equation:
T^{2} /\frac{4 \pi^{2} }{GM} = r^{3}  \\ &#10;T^{2} *\frac{GM}{4 \pi^{2} } = r^{3}

Rearrange:
r^{3} = T^{2} *\frac{GM}{4 \pi^{2} } \\ &#10;r^{3}= \frac{T^{2} *GM}{4 \pi^{2} }  \\ &#10;r^{3}= \frac{GMT^{2}}{4 \pi^{2} } \\ &#10;r^{3} = GMT^{2}/4 \pi^{2}

Since x^{3}= \sqrt[3]{x}, then
r^{3} = GMT^{2}/4 \pi^{2} \\ &#10;r= \sqrt[3]{GMT^{2}/4 \pi^{2}}
3 0
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