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4vir4ik [10]
2 years ago
9

At a coffee shop, the first 100 customers' orders were as follows. Smol Medium Large Hot 5 48 8 12 5 ll/ If we choose a customer

at random, what is the probability that his or her drink will be cold? [ ? 1%​

Mathematics
2 answers:
drek231 [11]2 years ago
6 0

Answer:

25%

Step-by-step explanation:

Tell me if I'm wrong. I apologize if I am.

Diano4ka-milaya [45]2 years ago
6 0

Answer:

25%

Step-by-step explanation:

A total of 25 get cold drinks, and there are 100 orders in total

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1 year ago
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7 0
3 years ago
Triangle abc is similar to triangle FGH solve for p plebs.
12345 [234]

The value of <em>p </em>is 21

Step-by-step explanation:

ΔABC ~ ΔFGH

\frac{ab}{fg}  =  \frac{bc}{gh}  \\  \frac{35}{p}  =  \frac{10}{6}  \\ p =  \frac{35 \times 6}{10}  \\ p =  \frac{210}{10}  \\ p = 21 \\  \\ or \\  \\  \frac{ab}{fg}  =  \frac{ac}{fh}  \\  \frac{35}{p}  =  \frac{30}{18}  \\ p =  \frac{35 \times 18}{30}  \\ p =  \frac{630}{30}  \\ p = 21

So, the value of <em>p</em> is 21

<em>Hope </em><em>it </em><em>helpful </em><em>and </em><em>useful </em><em>:</em><em>)</em>

5 0
3 years ago
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6 0
2 years ago
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The U.S. and many other countries have recently tightened airport security. A sociologist is interested in estimating the propor
melisa1 [442]

Answer:

0.0073 < 0.05, which means that we reject the null hypothesis and conclude that the true proportion of interest is higher than 0.7.

Step-by-step explanation:

Conduct a test to determine whether the true proportion of interest is higher than 0.7.

This means that the null hypothesis is: H_{0}: p = 0.7

And the alternate hypothesis is: H_{a}: p > 0.7

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.7 is tested at the null hypothesis:

This means that \mu = 0.7, \sigma = \sqrt{0.7*0.3}

The sociologist found that 375 of the 500 travelers randomly selected and interviewed indicated that the airports were safe.

This means that n = 500, X = \frac{375}{500} = 0.75

Value of the z-statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.75 - 0.7}{\frac{\sqrt{0.7*0.3}}{\sqrt{350}}}

z = 2.44

P-value of the test:

Probability of z being larger than 2.44, that is, a proportion larger than 0.75.

This is, looking at the z-table, 1 subtracted by the pvalue of Z = 2.44. S

Z = 2.44 has a pvalue of 0.9927

1 - 0.9927 = 0.0073

0.0073 < 0.05, which means that we reject the null hypothesis and conclude that the true proportion of interest is higher than 0.7.

8 0
3 years ago
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