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Lena [83]
3 years ago
14

25% of 120 = ......% of 40. What is the missing number?

Mathematics
1 answer:
densk [106]3 years ago
4 0

Answer:

75%

Step-by-step explanation:

25% of 120=120÷4=3

30/40=75%

Check:

75% of 40=30

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50 points help asap!
Luden [163]

Answer:

58 feet.

Step-by-step explanation

Since the angle given is across from the length we need to find and we are given the hypotenuse, we use sine.

Sin(46)=x/80 where x is the height of the triangle and 80 is the hypotenuse.

80sin(46)=x

x=57.55 or 58 feet.

8 0
3 years ago
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11.(02.03)
Marianna [84]

Answer:

step number 1 is incorrect.

Step-by-step explanation:

Here is the solution of this equation [2x-31-1=2].

2x-31-1=2

or 2x-31=2+1

or 2x=2+1+31

or 2x= 34

or x=34/2

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the answer of this equation is X=17.

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3 years ago
Find the solution of the differential equation dy/dt = ky, k a constant, that satisfies the given conditions. y(0) = 50, y(5) =
irga5000 [103]

Answer:  The required solution is y=50e^{0.1386t}.

Step-by-step explanation:

We are given to solve the following differential equation :

\dfrac{dy}{dt}=ky~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.

From equation (i), we have

\dfrac{dy}{y}=kdt.

Integrating both sides, we get

\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]

Also, the conditions are

y(0)=50\\\\\Rightarrow ae^0=50\\\\\Rightarrow a=50

and

y(5)=100\\\\\Rightarrow 50e^{5k}=100\\\\\Rightarrow e^{5k}=2\\\\\Rightarrow 5k=\log_e2\\\\\Rightarrow 5k=0.6931\\\\\Rightarrow k=0.1386.

Thus, the required solution is y=50e^{0.1386t}.

8 0
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maksim [4K]
<h2>Answer: 8</h2>

Step-by-step explanation:

10x+45 > 120\\10x+45-45 > 120-45\\10x > 75\\\frac{10x}{10} > \frac{75}{10} \\x > 7.5

Therefore, Mel has to work at least 7.5 hours or 8 total hours.

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2 years ago
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1/5 is the simplest form of the fraction
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