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LUCKY_DIMON [66]
3 years ago
8

∇f = λ∇g gives us the equations 4xy = 4λx, 2x2 = 8λy. The first equation implies that x = Incorrect: Your answer is incorrect. o

r λ = Correct: Your answer is correct. .
Mathematics
1 answer:
Vlad1618 [11]3 years ago
6 0

Answer:

The answer is correct

Step-by-step explanation:

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Please answer this correctly
Leona [35]

Answer:

The first answer.

Step-by-step explanation:

The first answer.

What was the temperature of the air?

'was 2C warmer than the surface of the ice'

warmer than= +2c

Temp. of ice=-2c

-2c+2c=0

7 0
3 years ago
Read 2 more answers
What is the inverse of y-2=7x
Galina-37 [17]

f-1(x) = x/7 – 2/7

there is the answer

6 0
3 years ago
The random variable X is normally distributed.
Nastasia [14]

Answer:

3

Step-by-step explanation:

because it tje best answer on there ferl me

6 0
3 years ago
Find m∠MON<br> I have a hard time with theses
fredd [130]

Answer:

m∠MON = 15°

Step-by-step explanation:

The given parameters are;

m∠LON = 77°

m∠LOM = 9·x + 44°

m∠MON = 6·x + 3°

By angle addition postulate, we have;

m∠LON = m∠LOM + m∠MON

Therefore, by substituting the known values, we have;

∴ 77° = 9·x + 44° + 6·x + 3°

77° = 9·x + 44° + 6·x + 3° = 15·x + 47°

77° = 15·x + 47°

77° - 47° = 15·x

15·x = 77° - 47° = 30°

15·x = 30°

x = 30°/15 = 2°

x = 2°

Given that m∠MON = 6·x + 3° and x = 2°, we have;

m∠MON = 6 × 2° + 3° = 12° + 3° = 15°

m∠MON = 15°.

3 0
3 years ago
A boat heads north across a river at a rate of 2 miles per hour. If the current is flow A boat heads north across a river at a r
Ivahew [28]

Answer:

\textrm{Resultant velocity}\ =\ \sqrt{29}\ miles/hour

along the direction 68.19° from north.

Step-by-step explanation:

Given,

  • speed of the boat, u= 2 miles/hour along north
  • speed of the river, v= 5 miles/ hour along east

Since, north and east are perpendicular to each other, so we can write the resultant velocity in vector form as,

\vec{r}\ =\ 2\hat{i}+5\hat{j}

Hence, the magnitude of resultant velocity can be written as

r\ =\ \sqrt{2^2+5^2}

  =\ \sqrt{4+25}

  =\ \sqrt{29}

Hence, the magnitude of resultant vector is \sqrt{29} moles/hour.

And the direction of the boat can be given by,

tan\theta\ =\ \dfrac{5}{2}

=>\ tan\theta\ =\ 2.5

=>\ \theta\ =\ tan^{-1}2.5

                 = 68.19°

Hence, the resultant velocity of boat is \sqrt{29} miles/hour along the direction making an angle 68.19° with the north.

8 0
3 years ago
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