Answer:
A. 0.035.
Explanation:
Female : cv-cSb+/cv-c+Sb
Male : cv-cSb/cv-cSb ( since test cross involves mating with a recessive parent )
Their progeny:
cv-cSb+/cv-cSb : parental
cv-c+Sb/cv-cSb : parental
cv-c+Sb+/cv-cSbc : recombinant
cv-cSb/cv-cSb : recombinant
Wild type phenotype (cv-c+Sb+/cv-cSbc) is a recombinant. Distance between the two genes is 7mu. Since map distance is equal to recombination percentage, there will be 7% recombinants in the progeny. Out of total 7% recombinants, 3.5% will be cv-c+Sb+/cv-cSbc( wild type) and rest 3.5% will be cv-cSb/cv-cSb (mutant type).
Hence, proportion of phenotypically wild-type individuals in the progeny of the test cross will be 3.5% or 0.035.
Answer: y = -6/5
Explanation:3x - 5y = 6 —> 5y = 3x - 6 —> y = (3/5)x -6/5
y intercept is where x = 0, where y = -6/5
and incidentally, the x intercept, where y = 0 is x = 2
Hiiiii I am sorry I don’t know lol I am so dumb
Answer:
The development of the brain continues past childhood. For example, if a monkey pushes a lever with its finger several thousand times a day, the Brain tissue that controls the finger changes as a result of the experience.
B. plants can begin to grow under snow, grow close to the ground, and flower quickly i think
