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3 years ago

I need help! I don't understand this!

Mathematics

1 answer:

Neporo4naja [7]3 years ago

4 0

When they say to solve for a variable, they want you to isolate/get the variable by itself.

5.) Solve for b (get b by itself)

$A=\frac{1}{2}bh$ Multiply 2 on both sides to get rid of the 1/2

2A = bh Divide h on both sides

$\frac{2A}{h} =b$

6.) Solve for r

$C=2\pi r$ Divide 2 and $\pi$ on both sides

$\frac{C}{2\pi } =r$

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Mr. and Mrs. Rainer took out a $240,000 loan to purchase their home. If the interest rate on the loan is 1.2% compounded bimonth

Bogdan [553]

Answer:

$103968.11

Step-by-step explanation:

Given information:

Principal amount = $240,000

Rate of interest = 1.2% = 0.012

Number of years = 30

Number of times in an year = 24

Formula for amount:

where

P is principal, r is rate of interest, t is number of years, n is number of times interest compounded in a year.

Now,

Hence, the interest is $103968.11.

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2 years ago

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3 years ago

Read 2 more answers

Solve using the quadratic formula. Show all work. Write each solution in simplest form. No decimals.

alexira [117]

Answer:

Option B

Step-by-step explanation:

Given quadratic equation is,

12a² + 9a + 7 = 0

By comparing this equation with standard quadratic equation,

hx² + kx + c = 0

h = 12, k = 9 and c = 7

By using quadratic formula,

a = $\frac{-k\pm\sqrt{k^2-4hc}}{2h}$

= $\frac{-9\pm\sqrt{9^2-4(12)(7)}}{2(12)}$

= $\frac{-9\pm\sqrt{81-336}}{2(12)}$

= $\frac{-9\pm\sqrt{-255}}{24}$

= $\frac{-9\pm i\sqrt{255}}{24}$

a = $\frac{-9+ i\sqrt{255}}{24},\frac{-9- i\sqrt{255}}{24}$

Therefore, Option B will be the correct option.

3 0

2 years ago

If the current in a circuit is 2 +j2 amps and the resistance is 3-j2 ohms, what is the voltage

victus00 [196]

Answer:

The voltage is 10 + 2j volts.

Step-by-step explanation:

Ohm's first law:

By Ohm's first law, the voltage is the multiplication of the current by the resistance, that is:

$V = R*i$

The voltage is measured in Volts, the current in amps and the resistance in ohms.

In this question:

Both the current and the resistance have complex parts. We have to know that:

$j^{2} = -1$

We have that:

$R = 3 - 2j, i = 2 + 2j$

Then

$V = R*i$

$V = (3 - 2j)*(2 + 2j)$

$V = 6 + 6j - 4j - 4j^{2}$

$V = 6 + 2j - 4(-1)$

$V = 10 + 2j$

The voltage is 10 + 2j volts.

4 0

3 years ago

Express 10 as a product of prime factors in index form

telo118 [61]

Answer:

product of prime factors: 2*5

8 0

2 years ago