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Alja [10]
3 years ago
15

18. Solve the inequality. Show your work. –6b > 42 or 4b > –4

Mathematics
2 answers:
grigory [225]3 years ago
6 0
-6b > 42 = b<-7
or
4b > -4 = b>-1
Hope this helps.
zhenek [66]3 years ago
4 0

Answer:

Divide each term by -6 and then simplify.    b < -6

divide each term by 2 and then simplify    b > -2

then graph the solution                              b < -6 and b > -2

Step-by-step explanation:


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What is the square root of twenty-five
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The square root of 25 would be 5!

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A family has two cars. The first car has a fuel efficiency of 15 miles per gallon of gas and the second has a fuel efficiency of
professor190 [17]

The fuel consumption of each of the cars during the week are as follows;

  • The first car consumes <u>20 gallons of fuel</u>.
  • The second car consumes <u>30 gallons of fuel</u>.

Reasons:

Fuel efficiency of the first car = 15 miles per  gallon

Fuel efficiency of the second car = 35 miles per gallon

Combined distance traveled by the two cars in a week = 1,350 miles

The total gas consumption during the week = 50 gallons

Let <em>x</em> represent the number of gallons consumed by the first car, and let <em>y</em>

represent the number of gallons consumed by the second car, we get the

following system of simultaneous equations;

  • 15·x + 35·y = 1,350...(1)
  • x + y = 50...(2)

Therefore;

y = 50 - x

Which gives;

15·x + 35 × (50 - x) = 1,350

15·x + 1,750 - 35·x = 1,350

1,750 - 1,350 = 35·x - 15·x = 20·x

400 = 20·x

x = 400 ÷ 20 = 20

  • The number of gallons consumed by the first car, x = <u>20 gallons</u>

From equation (2), we have;

x + y = 50

y = 50 - x

Therefore;

y = 50 - 20 = 30

  • The number of gallons consumed by the second car, y = <u>30 gallons</u>

Learn more about word problems that lead to simultaneous equations here:

brainly.com/question/1717365

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7 0
3 years ago
Read 2 more answers
In a semiconductor manufacturing process, three wafers from a lot are tested. Each wafer is classified as pass or fail. Assume t
Angelina_Jolie [31]

Answer:

P(X = 0) = 0.027

P(X = 1) = 0.189

P(X = 2) = 0.441

P(X = 3)= 0.343

Step-by-step explanation:

The probability mass function P(X = x) is the probability that X happens x times.

When n trials happen, for each x \leq n, the probability mass function is given by:

P(X = x) = pe_{n,x}.p^{x}.(1-p)^{n-x}

In which p is the probability that the event happens.

pe_{n,x}, is the permutation of n elements with x repetitions(when there are multiple events happening(like one passes and two not passing)). It can be calculated by the following formula:

pe_{n,x} = \frac{n!}{x!}

The sum of all P(X=x) must be 1.

In this problem

We have 3 trials, so n = 3

The probability that a wafer pass a test is 0.7, so p = 0.7

Determine the probability mass function of the number of wafers from a lot that pass the test.

P(X = 0) = (0.7)^{0}.(0.3)^{3} = 0.027

P(X = 1) = pe_{3,1}.(0.7).(0.3)^{2} = 0.189

P(X = 2) = pe_{3,2}.(0.7)^{2}.(0.3) = 0.441

P(X = 3) = (0.7)^{3} = 0.343

5 0
3 years ago
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