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defon
2 years ago
9

A rectangular prism has a length of 2 1/2 meters, a width of 4 meters, and a height of 2 1/4 meters. What is the volume of the p

rism? Enter your answer in the box as a simplified mixed number or a decimal. m?
Mathematics
1 answer:
TiliK225 [7]2 years ago
8 0

22.5 is the volume of the prism

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Identify all factors of the expression 12x^2-14x-6
Evgen [1.6K]

Let's solve this by using the quadratic formula:

\frac{-b+-\sqrt{b^2-4ac} }{2a}


Note that we only use the coefficients so a=12, b=-14, and c=-6.

Plug values in the quadratic equation:

\frac{ -  ( - 14)± \sqrt{ {( - 14)}^{2} - 4(12)( - 6) } }{2(12)}

And so by evaluating those values we obtain:

\frac{14+-\sqrt{484} }{24}=\frac{14+-22}{24}  \\\\

Now we have two answers which are our factors one where we add another where we subtract and so:

First factor:

\frac{14+22}{24}=\frac{36}{24}=\frac{3}{2}


Second Factor:

\frac{14-22}{24}=\frac{-8}{24}=-\frac{1}{3}


And so your factors are

\frac{3}{2},-\frac{1}{3}

meaning that those are your roots/x-intercepts.


6 0
3 years ago
Please help
gtnhenbr [62]

A line perpendicular to y = -2x + 5 will have an equation in the form of:

y = (1/2)x + b

Since the graph must intersect (-2,9), we plug in this point to solve for b.

9 = (1/2)*(-2) + b

9 = -1 + b

10 = b

So the equation is:

y = (1/2)x + 10

The answer is A.

7 0
2 years ago
In the game of​ roulette, a player can place a ​$9 bet on the number 11, and have a 1/38 probability of winning. If the metal ba
damaskus [11]

Answer:

1. What is the expected value of the game to the​ player?

Expected value= -$0.47368

2. If you played the game 1000​ times, how much would you expect to​ lose?

Expected value= -$473.68

Step-by-step explanation:

1. What is the expected value of the game to the​ player?

Expected value can tell how much you will gain/lose every time you do the game. To find the expected value you need to multiply every value with its chance to occur. There are two types of events here, winning and losing. You have 1/38 chance of winning $315 and 37/38 chance of losing $9.  

The expected value will be:

expected value= 1/38 * $315 + 37/38*(-$9) = $8.2894 - $8.7631

expected value= -$0.47368

You are expected to lose $0.47368 every time you play

2. If you played the game 1000​ times, how much would you expect to​ lose?

Expected value calculated for each roll. If you want to know how much you gain/lose by multiple rolls, you just need to multiply the expected value with the number of rolls. The game has negative expected value so you are expected to lose money instead of gaining money. The money you expected to lose will be:

number of roll * expected value

1000 timer * -$0.47368/time= -$473.68

You are expected to lose $473.68 if you play the game 1000 times.

6 0
2 years ago
2.35is equivalent too
rosijanka [135]
2.35 is equivalent to 235%
6 0
3 years ago
Read 2 more answers
Which situation is best represented by the following equation?
ololo11 [35]

Answer:

The first one, 14 weeks of dance classes.

Step-by-step explanation:

She paid $753.95 as a total for all of the classes, not just one week. She paid her registration free, which you subtract from 753.95 to get 630.00. She pays 45 per week, so you divide 630 by 45 to get the amount of weeks she attended dance classes, or 14 weeks.

8 0
2 years ago
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