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PilotLPTM [1.2K]
3 years ago
5

Which lists the fractions 2/3 , 5/6 , 7/12 from least to greatest

Mathematics
2 answers:
timofeeve [1]3 years ago
8 0

Answer:

7/12 , 2/3 , 5/6

Step-by-step explanation:

Firstly, give them a common denominator.

What do 3,6 and 12 all have in common? 12

So what we do to the bottom, we do to the top.

Multiply the 2/3 by 4 (3x4=12) to make 8/12.

Multiply the 5/6 by 2 (2x6=12) to make 10/12

7/12 already has 12 as the denominator.

Now order them.

7/12 , 8/12, 10/12.

Change them back to the original sums.

7/12 , 2/3 , 5/6

Zielflug [23.3K]3 years ago
5 0

Ans.

7/12 , 2/3 , 5/6

Why:

If we give all the fractions the same denominator then the fractions are, 8/12 , 10/12 , 7/12. We then can easily see what is the order. Once ordered correctly, just simplifiy.

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Y=5x 

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The Wall Street Journal reports that 33% of taxpayers with adjusted gross incomes between $30,000 and $60,000 itemized deduction
Len [333]

Answer:

(a) <em>                             </em><em>n</em> :      20           50          100         500

P (-200 < <em>X</em> - <em>μ </em>< 200) : 0.2886    0.4444    0.5954    0.9376

(b) The correct option is (b).

Step-by-step explanation:

Let the random variable <em>X</em> represent the amount of deductions for taxpayers with adjusted gross incomes between $30,000 and $60,000 itemized deductions on their federal income tax return.

The mean amount of deductions is, <em>μ</em> = $16,642 and standard deviation is, <em>σ</em> = $2,400.

Assuming that the random variable <em>X </em>follows a normal distribution.

(a)

Compute the probability that a sample of taxpayers from this income group who have itemized deductions will show a sample mean within $200 of the population mean as follows:

  • For a sample size of <em>n</em> = 20

P(\mu-200

                                           =P(-0.37

  • For a sample size of <em>n</em> = 50

P(\mu-200

                                           =P(-0.59

  • For a sample size of <em>n</em> = 100

P(\mu-200

                                           =P(-0.83

  • For a sample size of <em>n</em> = 500

P(\mu-200

                                           =P(-1.86

<em>                                  n</em> :      20           50          100         500

P (-200 < <em>X</em> - <em>μ </em>< 200) : 0.2886    0.4444    0.5954    0.9376

(b)

The law of large numbers, in probability concept, states that as we increase the sample size, the mean of the sample (\bar x) approaches the whole population mean (\mu_{x}).

Consider the probabilities computed in part (a).

As the sample size increases from 20 to 500 the probability that the sample mean is within $200 of the population mean gets closer to 1.

So, a larger sample increases the probability that the sample mean will be within a specified distance of the population mean.

Thus, the correct option is (b).

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Which expression is equivalent to (3−2^2) 5 ? 5−3^2 5−2^2 2^2−5 ​ 3^2−5
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Let's check all functions.
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  Evaluated with x means that</span> x = 3.
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2. f(x)=x²<span>-3x when evaulated with -3 give you the value of 3
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3. f(x)=x²<span>+2x when evaluated with -3 gives you the value of 3
</span>    Evaluated with -3 means that x = -3.
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4. f(x)=x²-3x when evaluated with -3 gives you the value of 3
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