Hello
<span>3 2/3 \ 3 2/9
(32/3) × (9/32) = 9/3=3</span>
Step-by-step explanation:
Annie = x
Brianna = y
Carly = z
Now,
x + y + z = 105 ...(1)
Carly has sold ten more than three times Brianna's sales.
z = 10 + 3y ...(2)
Brianna sold five more than Annie.
y = 5 + x ...(3)
Now,
z = 10 + 3y
z = 10 + 3(5 + x)
z = 10 + 15 + 3x
z = 25 + 3x
Now,
x + y + z = 105
x + (5 + x) + 25 + 3x = 105
5x + 30 = 105
5x = 105 - 30
5x = 75
5x/5 = 75/5
x = 15
So,
y = 5 + x
y = 5 + 15
y = 20
Now,
z = 25 + 3x
z = 25 + 3(15)
z = 25 + 45
z = 70
Thus,
Annie Sold 15 boxes
Brianna Sold 20 boxes
Carly Sold 70 boxes
Answer is 10.2 + 3.1x
Solve by combining like terms
Answer:
a) 8/10
b) 
c) Independent events
Step-by-step explanation:
The given information are;
The proportion of women than carries a mutation of the BRCA gene, P(A) = 1/600
The proportion of women in which the mutation develops breast cancer, P(B) = 8/10
a) The probability that a randomly selected woman will develop breast cancer given that she has a mutation of the BRCA gene is given as follows;
1 × P(B) = 1 × 8/10 = 8/10
b) The probability, P that a randomly selected woman woman will carry the mutation of the BRCA gene and will develop breast cancer is given as follows;
P(A) × P(B) = 1/600×8/10 = 1/750 = 
c) The events are dependent
Given that P(A) × P(B) = P(A∩B), the events of carrying the mutation and developing Breast cancer are independent events.
Answer:
1/6
1/12
1/2
Step-by-step explanation:
There are three possible outcomes in the left spinner, and four possible outcomes in the right spinner. So there are a total of 3×4=12 possible combinations. We can show that by making a grid:
![\left[\begin{array}{cccc}&R&B&G\\R&RR&BR&GR\\B&BR&BB&BG\\P&PR&BP&GP\\Y&RY&BY&GY\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D%26R%26B%26G%5C%5CR%26RR%26BR%26GR%5C%5CB%26BR%26BB%26BG%5C%5CP%26PR%26BP%26GP%5C%5CY%26RY%26BY%26GY%5Cend%7Barray%7D%5Cright%5D)
Of these 12 combinations, 2 show both spinners landing on the same color (RR and BB). So the probability is 2/12 = 1/6.
There is only 1 outcome in which the first spinner lands on R <em>and</em> the second spinner lands on P (PR), so the probability is 1/12.
There are 6 outcomes in which the first spinner lands on R <em>or</em> the second spinner lands on P (RR, BR, PR, RY, BP, GP). So the probability is 6/12 = 1/2.