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zhenek [66]
3 years ago
12

If f(x) = -2x – 3 and g(x) = x2 – 1 find f(-3) + g(3).

Mathematics
1 answer:
xenn [34]3 years ago
3 0

Answer:

Step-by-step explanation:

g ( f ( x ) ) = ( x+ 3) ^2

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Devon invests $9,000 in a savings account that pays 1.5% simple interest. How much will be in the account after 6 years if Devon
MAVERICK [17]
$810 because if you use the simple interest formula (s=p*r*t), you get $810 hope this helped!
4 0
3 years ago
Given the formula a = s2 + 3b - c , find the value of a when s = 7, b = 13 and c = -24.
galben [10]

Answer:

a = 112

Step-by-step explanation:

a =s^{2} +3b-c

Given that,

s = 7

b = 13

c = (-24)

Let's solve for a now.

a =s^{2} +3b-c

a = 7^{2} +3*13-(-24)\\

a=49+39+24\\

a=88+24

a=112

Hope this helps you.

Let me know if you have any other questions :-)

3 0
3 years ago
Which function shown has a greater average rate of change on the invertal calendar [-1,2]
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8 0
3 years ago
HELP ASAP : Find the largest value of n such that 5x^2+nx+48 can be factored as the product of two linear factors with integer c
Anna71 [15]

Answer:

n=241

Step-by-step explanation:

We are given

5x^2+nx+48

Let's assume it can be factored as

5x^2+nx+48=(5x-s)(x-r)

now, we can multiply right side

and then we can compare it

5x^2+nx+48=5x^2-5rx-sx+rs

5x^2+nx+48=5x^2-(5r+s)x+rs

now, we can compare coefficients

rs=48

5r+s=-n

n=-(5r+s)

now, we can find all possible factors of 48

and then we can assume possible prime factors of 48

48=-+(1\times 48)

48=-+(2\times 24)

48=-+(3\times 16)

48=-+(4\times 12)

48=-+(6\times 8)

Since, we have to find the largest value of n

So, we will get consider larger value of r because of 5r

and because n is negative of 5r+s

so, we will both n and r as negative

So, we can assume

r=-48 and s=-1

so, we get

n=-(5\times -48-1)

n=241


7 0
3 years ago
What does "As Much" mean in math? I am doing homework and I don't want to fail so I really need help.
igor_vitrenko [27]
It means the same used in a question like this, is 25 as much as 25.
4 0
3 years ago
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