If f(x) = -2x – 3 and g(x) = x2 – 1 find f(-3) + g(3).
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f(x) = (x + 2)² ⇒ f(x) = (x - (-2))² + 0 ⇒ h = -2 , k = 0
vertex: (-2, 0)
domain: R
range: <0, ∞)
axis of symetery: x = -2
up {a=1>0}
min: f(-2) = 0
graph: {f(0)=4}
