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3 years ago

What is the height of a cubic prism containing 125 cubes

Mathematics

1 answer:

ladessa [460]3 years ago

6 0

$s = \sqrt[3]{125}$

<h3>s=5 and height =5 cubes</h3><h3>hope it helps :-)</h3>

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I NEED HELP PLEASE !!!

VLD [36.1K]

Dividing by coefficient other than +1

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3 years ago

Find the perimeter of the pentagon MNPQR with vertices M(2, 4), N(5, 8), P(8, 4), Q(8, 1), and R(2, 1)

Gekata [30.6K]

Answer:

The pentagon MNPQR has a perimeter of 22 units.

Step-by-step explanation:

Geometrically speaking, the perimeter of the pentagon is the sum of the lengths of each side, that is:

$p = MN + NP + PQ + QR + RM$ (1)

$p = \sqrt{\overrightarrow{MN}\,\bullet \, \overrightarrow{MN}} + \sqrt{\overrightarrow{NP}\,\bullet \, \overrightarrow{NP}} + \sqrt{\overrightarrow{PQ}\,\bullet \, \overrightarrow{PQ}} + \sqrt{\overrightarrow{QR}\,\bullet \, \overrightarrow{QR}} + \sqrt{\overrightarrow{RM}\,\bullet \, \overrightarrow{RM}}$ (1b)

If we know that $M(x,y) = (2,4)$ , $N(x,y) = (5,8)$ , $P(x,y) = (8,4)$ , $Q(x,y) = (8,1)$ and $R(x,y) = (2,1)$ , then the perimeter of the pentagon MNPQR is:

$p =\sqrt{(5-2)^{2}+(8-4)^{2}} + \sqrt{(8-5)^{2}+(4-8)^{2}}+\sqrt{(8-8)^{2}+(1-4)^{2}}+\sqrt{(2-8)^{2}+(1-1)^{2}}+\sqrt{(2-2)^{2}+(4-1)^{2}}$ $p = \sqrt{3^{2}+4^{2}} + \sqrt{3^{2}+(-4)^{2}}+\sqrt{0^{2}+(-3)^{2}}+\sqrt{(-6)^{2}+0^{2}}+\sqrt{0^{2}+3^{2}}$

$p = 22$

The pentagon MNPQR has a perimeter of 22 units.

4 0

3 years ago

A research company found that 11% of the people that they called agreed to participate in a survey. If the company called 196 pe

natita [175]

Answer:

Step-by-step explanation:

Trust me

7 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%5Cunderline%7B%20%5Cunderline%7B%20%5Ctext%7BQuestion%7D%7D%7D%20%3A%20" id="TexFormula1"

Ghella [55]

Answer:

See Below.

Step-by-step explanation:

Statements: Reasons:

$1)\text{ } AD\text{ bisects } \angle BAC$ Given

$2)\text{ } \angle BAD \cong \angle CAD$ Definition of Bisector

$\displaystyle 3) \text{ } A D \parallel E C$ Given

$\displaystyle 4)\text{ } \angle CAD\cong \angle ACE$ Alternate Interior Angles Theorem*

$\displaystyle 5) \text{ } \angle BAD\cong \angle BEC$ Corresponding Angles Theorem*

$6)\text{ } \angle CAD\cong \angle BEC$ Substitution

$7)\text{ } \angle ACE\cong\angle BEC$ Substitution

$\displaystyle 8)\text{ } AC = A E$ Isosceles Theorem Converse

*Please refer to the attachment below.

Let me know if you have any questions!

3 0

3 years ago

Read 2 more answers

Use a linear approximation (or differentials) to estimate the given number.

bagirrra123 [75]

Would use the algorithm for solving square root.

For square root, √n

x₁ = 0.5(x₀ + n/x₀)

(This formula is known and for square root, and can be derived using Newton-Raphson's approximation equation)

Where x₀ is the initial guess. x₁ becomes the new guess.

For √100.6 let our initial guess be 10, x₀ = 10, n = 100.6

Our approximation shall be to 3 decimal places. Once we get the same answer twice we stop the algorithm.

x₀ = 10, x₁ = 0.5(x₀ + n/x₀), x₁ = 0.5(10 + 100.6/10) = 10.030, x₁ = 10.030

x₂ = 0.5(x₁ + n/x₁), x = 0.5(10.030 + 100.6/10.030) ≈10.015, x₂ ≈ 10.030 (to 3 decimal places)

Since x₂≈ x₁, the algorithm stops.

So the √100.6 is ≈ 10.030 to 3 decimal places.

I hope this helps.

4 0

3 years ago