1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
umka21 [38]
3 years ago
14

What is the solution to the system of equations below?

Mathematics
1 answer:
Burka [1]3 years ago
3 0

Answer:

  (x, y) = (-4, -15)

Step-by-step explanation:

You can equate the expressions for y and solve for x.

  3/4x -12 = -4x -31

Adding 4x+12 gives ...

  (4 3/4)x = -19

  (19/4)x = -19

Multiplying by 4/19, we find ...

  x = -4

Substituting that into the first equation, we can find y:

  y = (3/4)(-4) -12 = -15

The solution is (x, y) = (-4, -15).

You might be interested in
Deal 1: $16.05 for 5 Caramel apples Deal 2: $19.14 for 6 caramel
Dmitry [639]
Deal 2 is the best deal. Deal 1 is $3.21 per apple but Deal two is $3.19 per apple.
6 0
3 years ago
Read 2 more answers
Please solve this question!!​
GaryK [48]

Answer:  (i) 1/221     (ii) 11/221      (iii) 95/663        (iv) 1/663

<u>Step-by-step explanation:</u>

(i) A deck of cards contains 4 Kings out of 52 total cards

1st draw: 4 Kings out of 52 total cards → 4/52 = 1/13

2nd draw: 3 remaining Kings out of 51 total remaining cards  →  3/51 = 1/17

  <u>1st Draw </u>                   <u>2nd Draw </u>                  <u>Outcome</u>         <u>Probability</u>

 King: P(K) = 1/13        King: P(K₂/K₁) = 1/17     King, King       (1/13) x (1/17) = 1/221

*************************************************************************************************

(ii) A deck of cards contains 4 Jacks, 4 Queens, & 4 Kings out of 52 total cards

1st draw: 12 Face cards out of 52 total cards → 12/52 = 3/13

2nd draw: 11 remaining Face cards out of 51 total remaining cards  →  11/51

<u>1st Draw </u>                 <u>2nd Draw </u>                  <u>Outcome</u>       <u>Probability</u>

 Face: P(F) = 3/13    Face: P(F₂/F₁) = 11/51   Face,Face     (3/13) x (11/51) = 11/221

*************************************************************************************************

(iiI) A deck of cards contains 26 black cards out of 52 total cards but there are 2 black Jacks, 2 black Queens, and 2 black Kings.

1st draw: 20 Black (not Face) cards out of 52 total cards → 20/52 = 5/13

2nd draw: 19 remaining Black (not Face) cards out of 51 total remaining cards  →  19/51

  <u>1st Draw </u>                 <u>2nd Draw </u>                       <u>Outcome</u>   <u>Probability</u>

Black: P(B~) = 5/13   Black: P(B~₂/B~₁) = 19/51    B~,B~    (5/13) x (19/51) = 95/663

*************************************************************************************************

(ii) A deck of cards contains 4 Aces out of 52 total cards

1st draw: 4 Aces out of 52 total cards → 4/52 = 1/13

2nd draw: 1 Queen of Hearts out of 51 total remaining cards  →  1/51

  <u>1st Draw </u>                 <u>2nd Draw </u>                   <u>Outcome</u>         <u>Probability</u>

 Ace: P(A) = 1/13      Qh: P(Qh₂/A₁) = 1/51   Ace,Queen(h)   (1/13) x (1/51) = 1/663

7 0
4 years ago
Divide 32x3+48x2-40x by 8x
gregori [183]

Answer:16.5

Step-by-step explanation:

6 0
3 years ago
What would the graph of y=x look like? name three ordered pairs that lie on the line.
ololo11 [35]

-- The graph looks like a line that passes through the origin,
and slopes up to the right at a 45-degree angle.

-- Point #1 on the line:
. . . . . Pick any number. 
. . . . . Write it down twice.
. . . . . Call the first one 'x'.  Call the second one 'y'.

-- Point #2 on the line:
. . . . . Pick any other number. 
. . . . . Write it down twice.
. . . . . Call the first one 'x'.  Call the second one 'y'.

-- Point #3 on the line:
. . . . . Pick any other number. 
. . . . . Write it down twice.
. . . . . Call the first one 'x'.  Call the second one 'y'.

Rinse and repeat, as many times as you like,
until the novelty wears off and you lose interest.

3 0
3 years ago
Read 2 more answers
A baseball player hit 65 home runs in a season. Of the 65 home​ runs, 19 went to right​ field, 23 went to right-center​ field, 9
olchik [2.2K]

Answer:

a) 29.23% probability that a randomly selected home run was hit to right field

b) 29.23% probability that a randomly selected home run was hit to right field, which is not lower than 5% nor it is higher than 95%. So it was not unusual for this player to hit a home run to right field.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes. It is said to be unusual if it is lower than 5% or higher than 95%.

(a) What is the probability that a randomly selected home run was hit to right field?

Desired outcomes:

19 home runs hit to right field

Total outcomes:

65 home runs

19/65 = 0.2923

29.23% probability that a randomly selected home run was hit to right field

(b) Was it unusual for this player to hit a home run to right field?

29.23% probability that a randomly selected home run was hit to right field, which is not lower than 5% nor it is higher than 95%. So it was not unusual for this player to hit a home run to right field.

8 0
3 years ago
Other questions:
  • Jeff bought a new car $10,450. He know this car's value will decrease by 20% each year. Jeff writes the following function to mo
    15·1 answer
  • A number decreased by 3 times the sum of a number and 2 is 306
    8·1 answer
  • Whats the circumfrence of a cupcake. show all working
    14·1 answer
  • What is the answer is 8p =72 p=
    5·2 answers
  • Please help! I really really need it.
    5·1 answer
  • Samantha Cruz has 200 coins (quarters and dimes). She has $44.00. Write a system of equations and determine how many quarters= _
    13·1 answer
  • Which of the following is a function
    5·1 answer
  • Write the following statement as expression 50 more than x​
    8·2 answers
  • PLS!
    5·1 answer
  • If y varies directly as x and y=4 when x=8, find y when x=44.​
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!