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nataly862011 [7]
3 years ago
13

What is 9,2345 + 35.98

Mathematics
2 answers:
Sloan [31]3 years ago
8 0

Answer:

9,2380.98

Step-by-step explanation:

 92345

+00035.98

hoa [83]3 years ago
3 0

the answer is

92,380.98

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What does the expression 2(21x + 75) represent
Alla [95]

Answer:

42x+150

Step-by-step explanation:

=(2)(21x+75)

=(2)(21x)+(2)(75)

Is there a story that goes with the question.

3 0
3 years ago
Brockman Corporation's earnings per share were $3.50 last year, and its growth rate during the prior 5 years was 9.2% per year.
lilavasa [31]

Answer:

c. 12.48

Step-by-step explanation:

The earnings per share after t years can be modeled by the following equation:

E(t) = E(0)(1+r)^{t}

In which E(0) is the earnings last year and r is the growth rate, as a decimal.

Brockman Corporation's earnings per share were $3.50 last year, and its growth rate during the prior 5 years was 9.2% per year. Growth rate maintained.

This means that E(0) = 3.50, r = 0.092

So

E(t) = E(0)(1+r)^{t}

E(t) = 3.50(1+0.092)^{t}

E(t) = 3.50(1.092)^{t}

If that growth rate were maintained, how many years would it take for Brockman's EPS to triple?

This is t for which E(t) = 3*E(0) = 3*3.50 = 10.50.

So

E(t) = 3.50(1.092)^{t}

10.50 = 3.50(1.092)^{t}

(1.092)^{t} = \frac{10.50}{3.50}

(1.092)^{t} = 3

\log{(1.092)^{t}} = \log{3}

t\log{1.092} = \log{3}

t = \frac{\log{3}}{\log{1.092}}

t = 12.48

So the correct answer is:

c. 12.48

5 0
3 years ago
6y=24−3x i need what x is and what y is but i cant seem to get it right
Marta_Voda [28]

Step-by-step explanation:

6y=24-3x

6y/6=24-3x/6

y= 4-1/2x

x= -2y+8

8 0
4 years ago
Read 2 more answers
Find the value of the following expression: (2^8 ⋅ 5^−5 ⋅ 19^0)^−2 ⋅ 5 to the power of negative 2 over 2 to the power of 3, whol
koban [17]

Answer:

\large\boxed{\dfrac{5^2\cdot57}{2^{26}}=\dfrac{1425}{67108864}}

Step-by-step explanation:

\left(2^8\cdot5^{-5}\cdot19^0\right)^{-2}\cdot\left(\dfrac{5^{-2}}{2^3}\right)^4\cdot228\\\\\text{use}\ a^{-n}=\dfrac{1}{a^n}\ \text{and}\ a^0=1\ \text{and}\ (a^n)^m=a^{nm}\\\\=\left(2^8\cdot\dfrac{1}{5^5}\cdot1\right)^{-2}\cdot\left(\dfrac{\frac{1}{5^2}}{2^3}\right)^4\cdot228=\left(\dfrac{2^8}{5^5}\right)^{-2}\cdot\left(\dfrac{1}{2^35^2}\right)^4\cdot228

=\dfrac{(2^8)^{-2}}{(5^5)^{-2}}\cdot\dfrac{1^4}{(2^3)^4(5^2)^4}\cdot228=\dfrac{2^{-16}}{5^{-10}}\cdot\dfrac{1}{2^{12}5^8}\cdot228\\\\\text{use}\ a^n=\dfrac{1}{a^{-n}}\to\dfrac{1}{a^n}=a^{-n}\\\\=2^{-16}\cdot5^{10}\cdot2^{-12}\cdot5^{-8}\cdot228\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=2^{-16+(-12)}\cdot5^{10+(-8)}\cdot228=2^{-28}\cdot5^2\cdot228\\\\=2^{-28}\cdot5^2\cdot4\cdot57=2^{-28}\cdot5^2\cdot2^2\cdot57=2^{-28+2}\cdot5^2\cdot57\\\\=2^{-26}\cdot5^2\cdot57=\dfrac{5^2\cdot57}{2^{26}}

\large\boxed{\dfrac{5^2\cdot57}{2^{26}}=\dfrac{1425}{67108864}}

4 0
3 years ago
Write an
makkiz [27]
The answer is (x-y)^2
hope it helps!!!!!!
the formula is
(a-b)^2
and when you expand it, it becomes
a^2-2ab+b^2
8 0
3 years ago
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