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Pavlova-9 [17]
3 years ago
9

Elsa wants to draw a second rectangle that is the same length but is 3 times as wide. What is the width of Elsa's second rectang

le
Mathematics
1 answer:
Art [367]3 years ago
3 0

Answer:

Whatever the length and width of the first triangle are take them and multiply by three. Place them in their respective sides of the new rectangle. The answer should be 9.

Step-by-step explanation:

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12 subtracted from a number equals 25 find the number
belka [17]

Answer: 12-n=25

-n=25-12

-n=13

Step-by-step explanation:

6 0
3 years ago
2. Calculate the energy in joules of a photon whose frequency is 7.55×1014 Hz.
igomit [66]
The energy of a photon is given by
E = h × v

where:
E is the energy in joules/photon
'h' is the constant 6.63 × 10⁻³⁴
'v' is the frequency 7.55 × 10¹⁴

Substitute 'h' and 'v' into the formula we have

E = (6.63×10⁻³⁴) × (7.55×10¹⁴)
E = (6.63×7.55) × (10⁻³⁴ × 10¹⁴)
E = 50.0565 × 10⁽⁻³⁴⁺¹⁴⁾
E = 50 × 10⁻²⁰ joules/photon
8 0
3 years ago
It cost $5000 to feed
Mariulka [41]

Answer:

Okays so for 100 guests we can make the equation $5000 ÷ 100 = $50.00

For 100 guests at the wedding it would cost <u>$50.00</u> per plate

For 45 guests we can make the equation $2750 ÷ 45 = $61.111111111111, it would be a repeating decimal

For 45 guests at the wedding, it would cost <u>$61.111111111111</u>

I hope that this can help you! ^‿^

5 0
3 years ago
PLEASE HELP ASAP!! VERY IMPORTANT!!!!! (NUMBER 15!!)
maria [59]
The answer is c cause the answer is 16,741.55ft^2 and c is the closest to it
5 0
3 years ago
A rectangular box has a square base. The combined length of a side of the square base, and the height is 20 in. Let x be the len
aniked [119]

Answer:

a. V = (20-x) x^{2} in^{3}  

b . 1185.185 in^{3}

Step-by-step explanation:

Given that:

  • The height:  20  - x (in )
  • Let x be the length of a side of the base of the box (x>0)

a. Write a polynomial function in factored form modeling the volume V of the box.

As we know that, this is a rectangular box has a square base so the Volume of it is:

V = h *x^{2} in^{3}

<=> V = (20-x) x^{2}  in^{3}

b. What is the maximum possible volume of the box?

To  maximum the volume of it, we need to use first derivative of the volume.

<=> dV / Dx = -3x^{2} + 40x

Let dV / Dx = 0, we have:

-3x^{2} + 40x  = 0

<=> x = 40/3

=>the height h = 20/3

So  the maximum possible volume of the box is:

V = 20/3 * 40/3 *40/3

= 1185.185 in^{3}

7 0
3 years ago
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