Mike age is 3 less then twice the age of his brother nuke.
M = Mike's age now
N = Nuke's age now
M = 2N - 3
Ten years ago, four times nuke's age was one more mike's age.
M-10 = Mike's age 10 years ago
N-10 = Muke's age 10 years ago
4(N - 10) = 1 + M -10
what are their present ages
find M and N
substitute M = 2N - 3 into 4(N - 10) = 1 + M -10:
4(N - 10) = 1 + [2N - 3] - 10
4N - 40 = 2N - 12
2N = 28
N = 14
M = 2(14) - 3 = 28 - 3 = 25
Mike is 25 and Nuke is 14.
check:
4(14 - 10) = 4(4) = 16 = 26 -10 = 1 + 25 - 10
Answer:
It is a).
Step-by-step explanation:
The rule for change of base of a log is:
logb x = = loga x / loga b
So we have
log6 5 = log4 5 / log4 6.
Answer:
5
Step-by-step explanation:
This is a pretty simple question to answer, the one step that needs to be done is divide 78.5 by 15.7. You should come up with 5.
(0,6)(1,3)
slope(m) = (3 - 6) / (1 - 0) = -3
y - y1 = m(x - x1)
slope(m) = -3
(1,3)...x1 = 1 and y1 = 3
now we sub
y - 3 = -3(x - 1) <===
The measure off DF is 11.
In a circle inscribed within a triangle, the distance from each vertex of the triangle to the two nearest touchpoints (points of tangency on the circle) are equal. Since SD=4, DT=4 as well. Since UF=7, then FT=7.
DF=DT+TF=4+7=11.
