Answer:
photomath
Step-by-step explanation:
i dont know the answer but photomath is so much easier to get help.
Answer:
B
Step-by-step explanation:
It's domain is side from side and so it can't be c or d. and it range goes to a positive number so it has to be B.
To find the median, find the middle number. Since there are 10 numbers, find the 5th one and the 6th one and find their average.
The two numbers are both 9, so its safe to say that the median is 9.
to find the median of the first and quartile, you have to place a line where the median should be and find the median of that. Q1 and Q2 will be 5 and 11 (respectively).
Its easy to see that all the lines start at the lowest point given and end at the largest point given, so match Q1, the median, and Q3
The only line that has lines at the Q1, median, and Q3 we figured out is answer C, so therefore it is the answer.
Answer:
See explanation
Step-by-step explanation:
1. To rewrite the expression
use exponents property
So,
2. Why ![10^{\frac{1}{3}}=\sqrt[3]{10}?](https://tex.z-dn.net/?f=10%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B10%7D%3F)
Raise both sides to 10 power:
![(10^{\frac{1}{3}})^3=10^{\frac{1}{3}\cdot 3}=10^1=10\\ \\(\sqrt[3]{10})^3=10](https://tex.z-dn.net/?f=%2810%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%29%5E3%3D10%5E%7B%5Cfrac%7B1%7D%7B3%7D%5Ccdot%203%7D%3D10%5E1%3D10%5C%5C%20%5C%5C%28%5Csqrt%5B3%5D%7B10%7D%29%5E3%3D10)
So,
![(10^{\frac{1}{3}})^3=(\sqrt[3]{10} )^3](https://tex.z-dn.net/?f=%2810%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%29%5E3%3D%28%5Csqrt%5B3%5D%7B10%7D%20%29%5E3)
3. Simplify 
Use the Quotient of Powers Property:
Then
4. Solve 
First, note that 
then
Number 
is irrational number, number 10 is rational number. The sum of irrational and rational numbers is irrational number.
5. The same as option 4.
1/36 because there are 6 sides and the you are trying to figure out what the probiblity of rolling 1 out of 6 is
